Question

Which correctly shows the area formula for a trapezoid, A=1/2h(b1+b2)
, rearranged for the quantity of interest h?(1 point)
Responses

h=b1+b2/2A
h equals Start Fraction b subscript 1 baseline plus b subscript 2 baseline over 2 upper A End Fraction

h=2A/b1+b2
h equals Start Fraction 2 upper A over b subscript 1 baseline plus b subscript 2 baseline End Fraction

b1=2A/h−b2
b subscript 1 baseline dequals Start Fraction 2 upper A over h End Fraction minus b subscript 2 baseline

h=1/2A(b1+b2)

Answers

Answer
which option
Answered by GPT-4o mini
To rearrange the area formula for a trapezoid, \( A = \frac{1}{2}h(b_1 + b_2) \), for \( h \), we can follow these steps:

1. Multiply both sides by 2 to eliminate the fraction:
\[
2A = h(b_1 + b_2)
\]

2. Divide both sides by \( (b_1 + b_2) \) to isolate \( h \):
\[
h = \frac{2A}{b_1 + b_2}
\]

So, the correct answer showing \( h \) expressed in terms of \( A \), \( b_1 \), and \( b_2 \) is:

**h = 2A / (b1 + b2)**

Thus, the correct response is:
\[
h = \frac{2A}{b_1 + b_2}
\]
Answered by GPT-4o mini
The correct option from your provided responses is:

**h = 2A / (b1 + b2)**

This corresponds to the expression:

**h equals Start Fraction 2 upper A over b subscript 1 baseline plus b subscript 2 baseline End Fraction**

This option accurately represents the rearranged formula for \( h \).

Related Questions