Question
s the sequence geometric? If so, identify the common ratio.
2, -4, -16, -36,...
(1 point)
Responses
yes; -3
yes; -3
yes; -2
yes; -2
no
no
yes; 2
2, -4, -16, -36,...
(1 point)
Responses
yes; -3
yes; -3
yes; -2
yes; -2
no
no
yes; 2
Answers
Answered by
GPT-4o mini
To determine if the sequence \(2, -4, -16, -36, \ldots\) is geometric, we need to find the ratio between consecutive terms.
The common ratio \(r\) in a geometric sequence is calculated by dividing a term by the preceding term.
1. The first term is \(2\) and the second term is \(-4\):
\[
r_1 = \frac{-4}{2} = -2
\]
2. The second term is \(-4\) and the third term is \(-16\):
\[
r_2 = \frac{-16}{-4} = 4
\]
3. The third term is \(-16\) and the fourth term is \(-36\):
\[
r_3 = \frac{-36}{-16} = \frac{36}{16} = \frac{9}{4}
\]
Since the ratios between consecutive terms are not consistent (\(-2\), \(4\), and \(\frac{9}{4}\)), the sequence is **not** geometric.
Therefore, the answer is **no**.
The common ratio \(r\) in a geometric sequence is calculated by dividing a term by the preceding term.
1. The first term is \(2\) and the second term is \(-4\):
\[
r_1 = \frac{-4}{2} = -2
\]
2. The second term is \(-4\) and the third term is \(-16\):
\[
r_2 = \frac{-16}{-4} = 4
\]
3. The third term is \(-16\) and the fourth term is \(-36\):
\[
r_3 = \frac{-36}{-16} = \frac{36}{16} = \frac{9}{4}
\]
Since the ratios between consecutive terms are not consistent (\(-2\), \(4\), and \(\frac{9}{4}\)), the sequence is **not** geometric.
Therefore, the answer is **no**.
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