To solve the compound inequalities \(4x - 3 > 9\) and \(x + 6 > -2\), we will solve each inequality separately.
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Solving \(4x - 3 > 9\): \[ 4x - 3 > 9 \] Add 3 to both sides: \[ 4x > 12 \] Divide by 4: \[ x > 3 \]
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Solving \(x + 6 > -2\): \[ x + 6 > -2 \] Subtract 6 from both sides: \[ x > -8 \]
Now, we have two inequalities:
- \(x > 3\)
- \(x > -8\)
The solution set is the intersection of \(x > 3\) and \(x > -8\). Since \(x > 3\) is more restrictive than \(x > -8\), the solution set is simply:
\[ {x ,|, x > 3} \]
Thus, the correct response is:
\({x ,|, x > 3}\) (which corresponds to your last option).