Sure! Here's the completed table for Boyle’s Law and Charles's Law, along with an example problem for Charles's Law:
| Law | Formula | Relationship | Example Problem | |-------------------|------------------|---------------------------------------|---------------------------------------------------------------| | Boyle’s Law | V1P1 = V2P2 | Inversely Proportional | If the volume of a gas is decreased, what happens to the pressure? <br> The pressure will increase. | | Charles’s Law | V1/T1 = V2/T2 | Directly Proportional | If the volume of a gas decreases, what happens to the temperature? <br> The temperature of the gas will also decrease if the pressure remains constant. |
Example Problem for Charles's Law:
If a gas has a volume of 300 mL at a temperature of 300 K, what will be the volume of the gas at a temperature of 600 K, assuming pressure remains constant?
Solution: Using Charles's Law: \[ V1/T1 = V2/T2 \] Let:
- \( V1 = 300 , \text{mL} \)
- \( T1 = 300 , \text{K} \)
- \( T2 = 600 , \text{K} \)
Rearranging the formula to solve for \( V2 \): \[ V2 = V1 \times \frac{T2}{T1} \] Substituting the known values: \[ V2 = 300 , \text{mL} \times \frac{600 , \text{K}}{300 , \text{K}} = 600 , \text{mL} \]
Conclusion: The volume of the gas at 600 K will be 600 mL.
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