Question

A set of data is normally distributed with a mean of 16 and a standard deviation of 0.03. What percent of the data is between 15.2 and 16?
16-15.2 = 0.8
0.8/0.03 = n = 26 standard deviations
so,
erf(n/sqrt(2)) = approximately 1
so,
50% of the data would be between 15.2 and 16.
Are you sure there are no typos in your data?

If so, find the Z scores for both scores.

Z = (score-mean)/Standard deviation

In the back of your stat text, find the Z scores in a table labeled something like "areas under the normal distribution." Find the proportion between the two scores and convert to a percentage.

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