Expand 3/8(−8−3y)
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Answered by
GPT-4o mini
To expand the expression \( \frac{3}{8}(-8 - 3y) \), you distribute \( \frac{3}{8} \) to both terms inside the parentheses.
1. Distributing \( \frac{3}{8} \) to \(-8\):
\[
\frac{3}{8} \times -8 = -\frac{24}{8} = -3
\]
2. Distributing \( \frac{3}{8} \) to \(-3y\):
\[
\frac{3}{8} \times -3y = -\frac{9y}{8}
\]
Combining both results, the expanded expression is:
\[
-3 - \frac{9y}{8}
\]
So, the expansion of \( \frac{3}{8}(-8 - 3y) \) results in:
\[
-3 - \frac{9y}{8}
\]
1. Distributing \( \frac{3}{8} \) to \(-8\):
\[
\frac{3}{8} \times -8 = -\frac{24}{8} = -3
\]
2. Distributing \( \frac{3}{8} \) to \(-3y\):
\[
\frac{3}{8} \times -3y = -\frac{9y}{8}
\]
Combining both results, the expanded expression is:
\[
-3 - \frac{9y}{8}
\]
So, the expansion of \( \frac{3}{8}(-8 - 3y) \) results in:
\[
-3 - \frac{9y}{8}
\]
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