Asked by Rahamat Bello Bakwai
                11110 base 2 to 5 
            
            
        Answers
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                    Answered by
            GPT-4o mini
            
    To convert the binary number \( 11110_2 \) to base 5, we can follow these steps:
1. **Convert from base 2 to base 10**.
2. **Convert from base 10 to base 5**.
### Step 1: Convert from base 2 to base 10
The binary number \( 11110_2 \) can be converted to decimal (base 10) by applying the formula:
\[
n = b_k \cdot 2^k + b_{k-1} \cdot 2^{k-1} + ... + b_1 \cdot 2^1 + b_0 \cdot 2^0
\]
where \( b_k \) are the binary digits (from left to right).
So for \( 11110_2 \):
\[
11110_2 = 1 \cdot 2^4 + 1 \cdot 2^3 + 1 \cdot 2^2 + 1 \cdot 2^1 + 0 \cdot 2^0
\]
\[
= 1 \cdot 16 + 1 \cdot 8 + 1 \cdot 4 + 1 \cdot 2 + 0 \cdot 1
\]
\[
= 16 + 8 + 4 + 2 + 0 = 30
\]
### Step 2: Convert from base 10 to base 5
Now we convert \( 30_{10} \) to base 5 by repeatedly dividing by 5 and recording the remainders.
1. \( 30 \div 5 = 6 \) remainder \( 0 \)
2. \( 6 \div 5 = 1 \) remainder \( 1 \)
3. \( 1 \div 5 = 0 \) remainder \( 1 \)
Now, read the remainders from bottom to top:
So, \( 30_{10} = 110_5 \).
### Final Result
Therefore, the binary number \( 11110_2 \) is equal to \( 110_5 \) in base 5.
    
1. **Convert from base 2 to base 10**.
2. **Convert from base 10 to base 5**.
### Step 1: Convert from base 2 to base 10
The binary number \( 11110_2 \) can be converted to decimal (base 10) by applying the formula:
\[
n = b_k \cdot 2^k + b_{k-1} \cdot 2^{k-1} + ... + b_1 \cdot 2^1 + b_0 \cdot 2^0
\]
where \( b_k \) are the binary digits (from left to right).
So for \( 11110_2 \):
\[
11110_2 = 1 \cdot 2^4 + 1 \cdot 2^3 + 1 \cdot 2^2 + 1 \cdot 2^1 + 0 \cdot 2^0
\]
\[
= 1 \cdot 16 + 1 \cdot 8 + 1 \cdot 4 + 1 \cdot 2 + 0 \cdot 1
\]
\[
= 16 + 8 + 4 + 2 + 0 = 30
\]
### Step 2: Convert from base 10 to base 5
Now we convert \( 30_{10} \) to base 5 by repeatedly dividing by 5 and recording the remainders.
1. \( 30 \div 5 = 6 \) remainder \( 0 \)
2. \( 6 \div 5 = 1 \) remainder \( 1 \)
3. \( 1 \div 5 = 0 \) remainder \( 1 \)
Now, read the remainders from bottom to top:
So, \( 30_{10} = 110_5 \).
### Final Result
Therefore, the binary number \( 11110_2 \) is equal to \( 110_5 \) in base 5.
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