Asked by Rahamat Bello Bakwai
1010 base 2 to 5
Answers
Answered by
GPT-4o mini
To convert the binary number \( 1010_2 \) to base 5, we can follow these steps:
1. **Convert binary to decimal**.
2. **Convert decimal to base 5**.
### Step 1: Convert \( 1010_2 \) to decimal
To convert from binary to decimal, we can use the positional value of each digit. The binary number \( 1010_2 \) can be broken down as follows:
\[
1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 0 \times 2^0
\]
Calculating each term:
\[
= 1 \times 8 + 0 \times 4 + 1 \times 2 + 0 \times 1
\]
\[
= 8 + 0 + 2 + 0
\]
\[
= 10
\]
So, \( 1010_2 = 10_{10} \).
### Step 2: Convert decimal \( 10_{10} \) to base 5
Now, we will convert the decimal number \( 10 \) to base 5.
To do this, we divide the number by 5 and note the remainders:
1. \( 10 \div 5 = 2 \) with a remainder of \( 0 \).
2. \( 2 \div 5 = 0 \) with a remainder of \( 2 \).
Now we read the remainders from bottom to top. The remainders are \( 2 \) and \( 0 \), giving us:
\[
10_{10} = 20_5
\]
Putting it all together, the binary number \( 1010_2 \) converts to \( 20_5 \) in base 5.
1. **Convert binary to decimal**.
2. **Convert decimal to base 5**.
### Step 1: Convert \( 1010_2 \) to decimal
To convert from binary to decimal, we can use the positional value of each digit. The binary number \( 1010_2 \) can be broken down as follows:
\[
1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 0 \times 2^0
\]
Calculating each term:
\[
= 1 \times 8 + 0 \times 4 + 1 \times 2 + 0 \times 1
\]
\[
= 8 + 0 + 2 + 0
\]
\[
= 10
\]
So, \( 1010_2 = 10_{10} \).
### Step 2: Convert decimal \( 10_{10} \) to base 5
Now, we will convert the decimal number \( 10 \) to base 5.
To do this, we divide the number by 5 and note the remainders:
1. \( 10 \div 5 = 2 \) with a remainder of \( 0 \).
2. \( 2 \div 5 = 0 \) with a remainder of \( 2 \).
Now we read the remainders from bottom to top. The remainders are \( 2 \) and \( 0 \), giving us:
\[
10_{10} = 20_5
\]
Putting it all together, the binary number \( 1010_2 \) converts to \( 20_5 \) in base 5.
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