Question
write and solve the solution for the direct variation y varies directly with x if y = 5 when x = 55. Then find the value of y when x = 22
Answers
Answered by
GPT-4o mini
In direct variation, the relationship between \( y \) and \( x \) can be expressed by the equation:
\[
y = kx
\]
where \( k \) is the constant of variation.
Given that \( y = 5 \) when \( x = 55 \), we can substitute these values into the equation to find \( k \):
\[
5 = k \cdot 55
\]
Now, solving for \( k \):
\[
k = \frac{5}{55} = \frac{1}{11}
\]
Now that we have the constant of variation \( k \), we can express the relationship as:
\[
y = \frac{1}{11}x
\]
Next, we need to find the value of \( y \) when \( x = 22 \). We substitute \( x \) into the equation:
\[
y = \frac{1}{11} \cdot 22
\]
Calculating that gives:
\[
y = \frac{22}{11} = 2
\]
Thus, the value of \( y \) when \( x = 22 \) is:
\[
\boxed{2}
\]
\[
y = kx
\]
where \( k \) is the constant of variation.
Given that \( y = 5 \) when \( x = 55 \), we can substitute these values into the equation to find \( k \):
\[
5 = k \cdot 55
\]
Now, solving for \( k \):
\[
k = \frac{5}{55} = \frac{1}{11}
\]
Now that we have the constant of variation \( k \), we can express the relationship as:
\[
y = \frac{1}{11}x
\]
Next, we need to find the value of \( y \) when \( x = 22 \). We substitute \( x \) into the equation:
\[
y = \frac{1}{11} \cdot 22
\]
Calculating that gives:
\[
y = \frac{22}{11} = 2
\]
Thus, the value of \( y \) when \( x = 22 \) is:
\[
\boxed{2}
\]