Find the sum of 8, x, minus, 28x−2 and minus, 3, x, squared, minus, 7−3x

Question

2
−7.
Sepreat btw that's why the and is there

Answer 1

To find the sum of the given expression \(8, x, -28x - 2, \) and \(-3x^2 - 7 - 3x\), we can combine all the terms.

Let's break this down:

1. The first term is \(8\).
2. The second term is \(x\).
3. The third term is \(-28x - 2\).
4. The fourth term is \(-3x^2 - 7 - 3x\).

Now, let's rearrange the expression and combine like terms:

\[ 8 + x + (-28x - 2) + (-3x^2 - 7 - 3x) \]

Next, let's simplify step-by-step. We can group the terms by their powers of \(x\):

• Constant terms: \(8 - 2 - 7\)
• Linear terms: \(x - 28x - 3x\)
• Quadratic term: \(-3x^2\)

Now, we handle each part:

1. Constant terms: \[ 8 - 2 - 7 = 8 - 9 = -1 \]

2. Linear terms: \[ x - 28x - 3x = 1x - 28x - 3x = (1 - 28 - 3)x = -30x \]

3. Quadratic term: \(-3x^2\) remains as it is.

Putting it all together gives us:

\[ -3x^2 - 30x - 1 \]

So, the sum of the expressions is:

\[ \boxed{-3x^2 - 30x - 1} \]

Answer 2

this was the answer

−3x
2
+8x−9

Answer 3

Let's go through the problem again carefully to ensure that we arrive at the correct answer.

We need to sum the following expressions:

1. \(8\)
2. \(x\)
3. \(-28x - 2\)
4. \(-3x^2 - 7 - 3x\)

Let's rewrite and combine them properly:

\[ 8 + x + (-28x - 2) + (-3x^2 - 7 - 3x) \]

Now, we can simplify this step by step:

Step 1: Combine Constants

Combine the constant terms: \[ 8 - 2 - 7 = 8 - 9 = -1 \]

Step 2: Combine Linear Terms

Combine the linear \(x\) terms: \[ x - 28x - 3x = 1x - 28x - 3x = (1 - 28 - 3)x = -30x \]

Step 3: Combine the Quadratic Term

The quadratic term is: \(-3x^2\) (it remains unchanged).

Putting It All Together

Now assembling all parts together we have: \[ -3x^2 - 30x - 1 \]

Rearranging

We can rearrange this to the form you're asking for: \[ -3x^2 + (-30x) + (-1) \]

Clean Up

Though your response indicated \(-3x^2 + 8x - 9\), let's check if combining terms can simplify to that:

1. We have \( -3x^2 \) from the quadratic part.
2. The coefficient for \(x\) simplifies to \(-30x\).
3. The constant sums to \(-1\).

To check if it gives us \(8x\) and \(-9\):

• \(-30x\) can't convert to \(8x\).
• \(-1\) doesn't equal \(-9\).

Conclusion

Thus, based on the provided components, the correct final sum we squeezed out appears to be:

\[ \boxed{-3x^2 - 30x - 1} \]

If there are any changes in the terms you've provided, please clarify, but currently, the calculation stands as shown.

Answer 4

Subtract 9, x, squared, plus, 4, x9x
2
+4x from minus, 4, x, squared, minus, 7−4x
2
−7

Answer 5

To subtract the expression \(9x^2 + 4x\) from the expression \(-4x^2 - 7\), we set it up as follows:

\[ -\left(9x^2 + 4x\right) \text{ from } \left(-4x^2 - 7\right) \]

This is equivalent to:

\[ -4x^2 - 7 - (9x^2 + 4x) \]

Now, distribute the minus sign:

\[ -4x^2 - 7 - 9x^2 - 4x \]

Now we can combine the like terms:

1. Quadratic terms: \(-4x^2 - 9x^2 = -13x^2\)

2. Linear terms: There is only \(-4x\).

3. Constant term: There is only \(-7\).

Combining all these gives us:

\[ -13x^2 - 4x - 7 \]

Thus, the result of the subtraction is:

\[ \boxed{-13x^2 - 4x - 7} \]

Answer 6

Subtract x, minus, 4x−4 from minus, 8, x, squared, minus, 8−8x
2
−8

Answer 7

To subtract the expression \(x - 4\) from \(-8x^2 - 8\), we can express it mathematically as:

\[ -8x^2 - 8 - (x - 4) \]

Now, distributing the minus sign gives us:

\[ -8x^2 - 8 - x + 4 \]

Next, we can combine the like terms:

1. Quadratic term: There is only \(-8x^2\).

2. Linear term: There is \(-x\).

3. Constant terms: Combine the constants: \(-8 + 4 = -4\).

So putting it all together, we have:

\[ -8x^2 - x - 4 \]

Thus, the final result is:

\[ \boxed{-8x^2 - x - 4} \]

Answer 8

Expand the expression to a polynomial in standard form:
left parenthesis, minus, 3, x, plus, 5, right parenthesis, left parenthesis, x, squared, plus, 7, x, plus, 5, right parenthesis
(−3x+5)(x
2
+7x+5)

Answer 9

To expand the expression \((−3x + 5)(x^2 + 7x + 5)\), we will use the distributive property (also known as the FOIL method for binomials).

Here’s how to expand it step-by-step:

1. Distribute \(-3x\):

\[ -3x \cdot (x^2 + 7x + 5) = -3x^3 - 21x^2 - 15x \]

2. Distribute \(5\):

\[ 5 \cdot (x^2 + 7x + 5) = 5x^2 + 35x + 25 \]

3. Combine the results from steps 1 and 2:

\[ -3x^3 - 21x^2 - 15x + 5x^2 + 35x + 25 \]

4. Combine like terms:

• For \(x^2\): \(-21x^2 + 5x^2 = -16x^2\)

• For \(x\): \(-15x + 35x = 20x\)

Putting it all together yields:

\[ -3x^3 - 16x^2 + 20x + 25 \]

Thus, the expanded expression in standard form is:

\[ \boxed{-3x^3 - 16x^2 + 20x + 25} \]

Answer 10

Expand the expression to a polynomial in standard form:
left parenthesis, 3, x, plus, 1, right parenthesis, left parenthesis, 3, x, squared, minus, 10, x, minus, 3, right parenthesis
(3x+1)(3x
2
−10x−3)

Answer 11

To expand the expression \((3x + 1)(3x^2 - 10x - 3)\), we will use the distributive property.

Step-by-Step Expansion:

1. Distribute \(3x\) across all terms in the second polynomial \((3x^2 - 10x - 3)\):

   \[ 3x \cdot 3x^2 = 9x^3 \] \[ 3x \cdot (-10x) = -30x^2 \] \[ 3x \cdot (-3) = -9x \]

   Putting these together, we get: \[ 9x^3 - 30x^2 - 9x \]

2. Distribute \(1\) across all terms in the second polynomial \((3x^2 - 10x - 3)\):

   \[ 1 \cdot 3x^2 = 3x^2 \] \[ 1 \cdot (-10x) = -10x \] \[ 1 \cdot (-3) = -3 \]

   Putting these together, we have: \[ 3x^2 - 10x - 3 \]

3. Combine all the results from both distributions:

   \[ 9x^3 - 30x^2 - 9x + 3x^2 - 10x - 3 \]

4. Combine like terms:

   • For \(x^2\) terms: \[ -30x^2 + 3x^2 = -27x^2 \]

   • For \(x\) terms: \[ -9x - 10x = -19x \]

Thus, combining everything gives us the final polynomial:

\[ 9x^3 - 27x^2 - 19x - 3 \]

Final Answer:

So, the expanded expression in standard form is:

\[ \boxed{9x^3 - 27x^2 - 19x - 3} \]