Question

Find the sum of 8, x, minus, 28x−2 and minus, 3, x, squared, minus, 7−3x
2
−7.
Sepreat btw that's why the and is there

Answer 1

this was the answer

−3x
2
+8x−9

Answer 2

Subtract 9, x, squared, plus, 4, x9x
2
+4x from minus, 4, x, squared, minus, 7−4x
2
−7

Answer 3

Subtract x, minus, 4x−4 from minus, 8, x, squared, minus, 8−8x
2
−8

Answer 4

Expand the expression to a polynomial in standard form:
left parenthesis, minus, 3, x, plus, 5, right parenthesis, left parenthesis, x, squared, plus, 7, x, plus, 5, right parenthesis
(−3x+5)(x
2
+7x+5)

Answer 5

Expand the expression to a polynomial in standard form:
left parenthesis, 3, x, plus, 1, right parenthesis, left parenthesis, 3, x, squared, minus, 10, x, minus, 3, right parenthesis
(3x+1)(3x
2
−10x−3)

Answer 6

To find the sum of the given expression \(8, x, -28x - 2, \) and \(-3x^2 - 7 - 3x\), we can combine all the terms.

Let's break this down:

1. The first term is \(8\).
2. The second term is \(x\).
3. The third term is \(-28x - 2\).
4. The fourth term is \(-3x^2 - 7 - 3x\).

Now, let's rearrange the expression and combine like terms:

\[
8 + x + (-28x - 2) + (-3x^2 - 7 - 3x)
\]

Next, let's simplify step-by-step. We can group the terms by their powers of \(x\):

- Constant terms: \(8 - 2 - 7\)
- Linear terms: \(x - 28x - 3x\)
- Quadratic term: \(-3x^2\)

Now, we handle each part:

1. **Constant terms:**
\[
8 - 2 - 7 = 8 - 9 = -1
\]

2. **Linear terms:**
\[
x - 28x - 3x = 1x - 28x - 3x = (1 - 28 - 3)x = -30x
\]

3. **Quadratic term:**
\(-3x^2\) remains as it is.

Putting it all together gives us:

\[
-3x^2 - 30x - 1
\]

So, the sum of the expressions is:

\[
\boxed{-3x^2 - 30x - 1}
\]

Answer 7

Let's go through the problem again carefully to ensure that we arrive at the correct answer.

We need to sum the following expressions:

1. \(8\)
2. \(x\)
3. \(-28x - 2\)
4. \(-3x^2 - 7 - 3x\)

Let's rewrite and combine them properly:

\[
8 + x + (-28x - 2) + (-3x^2 - 7 - 3x)
\]

Now, we can simplify this step by step:

### Step 1: Combine Constants
Combine the constant terms:
\[
8 - 2 - 7 = 8 - 9 = -1
\]

### Step 2: Combine Linear Terms
Combine the linear \(x\) terms:
\[
x - 28x - 3x = 1x - 28x - 3x = (1 - 28 - 3)x = -30x
\]

### Step 3: Combine the Quadratic Term
The quadratic term is:
\(-3x^2\) (it remains unchanged).

### Putting It All Together
Now assembling all parts together we have:
\[
-3x^2 - 30x - 1
\]

### Rearranging
We can rearrange this to the form you're asking for:
\[
-3x^2 + (-30x) + (-1)
\]

### Clean Up
Though your response indicated \(-3x^2 + 8x - 9\), let's check if combining terms can simplify to that:

1. We have \( -3x^2 \) from the quadratic part.
2. The coefficient for \(x\) simplifies to \(-30x\).
3. The constant sums to \(-1\).

To check if it gives us \(8x\) and \(-9\):
- \(-30x\) can't convert to \(8x\).
- \(-1\) doesn't equal \(-9\).

### Conclusion
Thus, based on the provided components, the correct final sum we squeezed out appears to be:

\[
\boxed{-3x^2 - 30x - 1}
\]

If there are any changes in the terms you've provided, please clarify, but currently, the calculation stands as shown.

Answer 8

To subtract the expression \(9x^2 + 4x\) from the expression \(-4x^2 - 7\), we set it up as follows:

\[
-\left(9x^2 + 4x\right) \text{ from } \left(-4x^2 - 7\right)
\]

This is equivalent to:

\[
-4x^2 - 7 - (9x^2 + 4x)
\]

Now, distribute the minus sign:

\[
-4x^2 - 7 - 9x^2 - 4x
\]

Now we can combine the like terms:

1. **Quadratic terms:**
\(-4x^2 - 9x^2 = -13x^2\)

2. **Linear terms:**
There is only \(-4x\).

3. **Constant term:**
There is only \(-7\).

Combining all these gives us:

\[
-13x^2 - 4x - 7
\]

Thus, the result of the subtraction is:

\[
\boxed{-13x^2 - 4x - 7}
\]

Answer 9

To subtract the expression \(x - 4\) from \(-8x^2 - 8\), we can express it mathematically as:

\[
-8x^2 - 8 - (x - 4)
\]

Now, distributing the minus sign gives us:

\[
-8x^2 - 8 - x + 4
\]

Next, we can combine the like terms:

1. **Quadratic term:**
There is only \(-8x^2\).

2. **Linear term:**
There is \(-x\).

3. **Constant terms:**
Combine the constants: \(-8 + 4 = -4\).

So putting it all together, we have:

\[
-8x^2 - x - 4
\]

Thus, the final result is:

\[
\boxed{-8x^2 - x - 4}
\]

Answer 10

To expand the expression \((−3x + 5)(x^2 + 7x + 5)\), we will use the distributive property (also known as the FOIL method for binomials).

Here’s how to expand it step-by-step:

1. **Distribute \(-3x\)**:

\[
-3x \cdot (x^2 + 7x + 5) = -3x^3 - 21x^2 - 15x
\]

2. **Distribute \(5\)**:

\[
5 \cdot (x^2 + 7x + 5) = 5x^2 + 35x + 25
\]

3. **Combine the results from steps 1 and 2**:

\[
-3x^3 - 21x^2 - 15x + 5x^2 + 35x + 25
\]

4. **Combine like terms**:

- For \(x^2\):
\(-21x^2 + 5x^2 = -16x^2\)

- For \(x\):
\(-15x + 35x = 20x\)

Putting it all together yields:

\[
-3x^3 - 16x^2 + 20x + 25
\]

Thus, the expanded expression in standard form is:

\[
\boxed{-3x^3 - 16x^2 + 20x + 25}
\]

Answer 11

To expand the expression \((3x + 1)(3x^2 - 10x - 3)\), we will use the distributive property.

### Step-by-Step Expansion:

1. **Distribute \(3x\)** across all terms in the second polynomial \((3x^2 - 10x - 3)\):

\[
3x \cdot 3x^2 = 9x^3
\]
\[
3x \cdot (-10x) = -30x^2
\]
\[
3x \cdot (-3) = -9x
\]

Putting these together, we get:
\[
9x^3 - 30x^2 - 9x
\]

2. **Distribute \(1\)** across all terms in the second polynomial \((3x^2 - 10x - 3)\):

\[
1 \cdot 3x^2 = 3x^2
\]
\[
1 \cdot (-10x) = -10x
\]
\[
1 \cdot (-3) = -3
\]

Putting these together, we have:
\[
3x^2 - 10x - 3
\]

3. **Combine all the results from both distributions**:

\[
9x^3 - 30x^2 - 9x + 3x^2 - 10x - 3
\]

4. **Combine like terms**:

- For \(x^2\) terms:
\[
-30x^2 + 3x^2 = -27x^2
\]

- For \(x\) terms:
\[
-9x - 10x = -19x
\]

Thus, combining everything gives us the final polynomial:

\[
9x^3 - 27x^2 - 19x - 3
\]

### Final Answer:
So, the expanded expression in standard form is:

\[
\boxed{9x^3 - 27x^2 - 19x - 3}
\]