John was told that the rectangle had a side length of

5
𝑥
+
14

𝑓
𝑡
5x+14 ft and the other side length was
5
𝑥
+
26.
5x+26. If the perimeter of the rectangle was
230.0

𝑓
𝑡
230.0 ft then what is the value of
𝑥
x ?

1 answer

To find the value of \( x \), we start with the formula for the perimeter \( P \) of a rectangle, which is given by:

\[ P = 2(\text{length} + \text{width}) \]

Given that one side length (width) is \( 5x + 14 \) ft and the other side length (length) is \( 5x + 26 \) ft, we can set up the equation for the perimeter:

\[ 230 = 2((5x + 14) + (5x + 26)) \]

First, combine the expressions inside the parentheses:

\[ (5x + 14) + (5x + 26) = 5x + 14 + 5x + 26 = 10x + 40 \]

Now substitute this back into the perimeter equation:

\[ 230 = 2(10x + 40) \]

Next, simplify the equation by distributing the \( 2 \):

\[ 230 = 20x + 80 \]

Now, to isolate \( x \), subtract \( 80 \) from both sides:

\[ 230 - 80 = 20x \ 150 = 20x \]

Now, divide both sides by \( 20 \):

\[ x = \frac{150}{20} \ x = 7.5 \]

Thus, the value of \( x \) is:

\[ \boxed{7.5} \]