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Apply the product rule of integer exponents to find the numerical equivalent of 12^β5β 12^7. Show your work and explain how you...Asked by No name π«¦
Apply the product rule of integer exponents to find the numerical equivalent of 12^-5 * 12^7. Show your work, and explain how do use the product rule of integer exponents
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Answered by
No name π«¦
Can you do it a little shorter
Answered by
GPT-4o mini
To find the numerical equivalent of \( 12^{-5} \times 12^{7} \), we can use the *product rule of integer exponents*, which states that when multiplying two powers with the same base, we add their exponents. The rule can be expressed as:
\[
a^m \times a^n = a^{m+n}
\]
In our case, the base \( a \) is \( 12 \), \( m \) is \( -5 \), and \( n \) is \( 7 \).
Applying the product rule, we have:
\[
12^{-5} \times 12^{7} = 12^{-5 + 7}
\]
Now, we calculate the exponent:
\[
-5 + 7 = 2
\]
Thus, we get:
\[
12^{-5} \times 12^{7} = 12^{2}
\]
Next, we can find the numerical equivalent of \( 12^{2} \):
\[
12^{2} = 12 \times 12 = 144
\]
Therefore, the numerical equivalent of \( 12^{-5} \times 12^{7} \) is \( 144 \).
In summary, we applied the product rule of integer exponents by adding the exponents of the same base, simplified to find \( 12^{2} \), and calculated the final numerical value as \( 144 \).
\[
a^m \times a^n = a^{m+n}
\]
In our case, the base \( a \) is \( 12 \), \( m \) is \( -5 \), and \( n \) is \( 7 \).
Applying the product rule, we have:
\[
12^{-5} \times 12^{7} = 12^{-5 + 7}
\]
Now, we calculate the exponent:
\[
-5 + 7 = 2
\]
Thus, we get:
\[
12^{-5} \times 12^{7} = 12^{2}
\]
Next, we can find the numerical equivalent of \( 12^{2} \):
\[
12^{2} = 12 \times 12 = 144
\]
Therefore, the numerical equivalent of \( 12^{-5} \times 12^{7} \) is \( 144 \).
In summary, we applied the product rule of integer exponents by adding the exponents of the same base, simplified to find \( 12^{2} \), and calculated the final numerical value as \( 144 \).
Answered by
GPT-4o mini
Sure! Hereβs a more concise explanation:
To find \( 12^{-5} \times 12^{7} \) using the product rule of integer exponents, we apply the rule:
\[
a^m \times a^n = a^{m+n}
\]
Here, \( a = 12 \), \( m = -5 \), and \( n = 7 \):
\[
12^{-5} \times 12^{7} = 12^{-5 + 7} = 12^{2}
\]
Now, calculating \( 12^{2} \):
\[
12^{2} = 144
\]
Thus, \( 12^{-5} \times 12^{7} = 144 \).
To find \( 12^{-5} \times 12^{7} \) using the product rule of integer exponents, we apply the rule:
\[
a^m \times a^n = a^{m+n}
\]
Here, \( a = 12 \), \( m = -5 \), and \( n = 7 \):
\[
12^{-5} \times 12^{7} = 12^{-5 + 7} = 12^{2}
\]
Now, calculating \( 12^{2} \):
\[
12^{2} = 144
\]
Thus, \( 12^{-5} \times 12^{7} = 144 \).
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