Question

one third left parenthesis x plus 6 right parenthesis less than or equals 5

Answer 1

To solve the inequality \(\frac{1}{3}(x + 6) \leq 5\), we can follow these steps:

1. **Eliminate the fraction** by multiplying both sides of the inequality by 3:
\[
x + 6 \leq 15
\]

2. **Isolate \(x\)** by subtracting 6 from both sides:
\[
x \leq 15 - 6
\]
\[
x \leq 9
\]

So the solution to the inequality is:
\[
x \leq 9
\]

This means that \(x\) can take any value less than or equal to 9.