one third left parenthesis x plus 6 right parenthesis less than or equals 5

Answer 1

To solve the inequality \(\frac{1}{3}(x + 6) \leq 5\), we can follow these steps:

1. Eliminate the fraction by multiplying both sides of the inequality by 3: \[ x + 6 \leq 15 \]

2. Isolate \(x\) by subtracting 6 from both sides: \[ x \leq 15 - 6 \] \[ x \leq 9 \]

So the solution to the inequality is: \[ x \leq 9 \]

This means that \(x\) can take any value less than or equal to 9.