6 y minus 4 minus 2 y plus 3equals0

Answer 1

To solve the equation \(6y - 4 - 2y + 3 = 0\), we can start by combining like terms.

1. Combine \(6y\) and \(-2y\): \[ 6y - 2y = 4y \]

2. Combine \(-4\) and \(3\): \[ -4 + 3 = -1 \]

Now, substitute these back into the equation: \[ 4y - 1 = 0 \]

3. Add \(1\) to both sides: \[ 4y = 1 \]

4. Divide by \(4\): \[ y = \frac{1}{4} \]

Thus, the solution to the equation is: \[ y = \frac{1}{4} \]