Question

6 y minus 4 minus 2 y plus 3equals0

Answer 1

To solve the equation \(6y - 4 - 2y + 3 = 0\), we can start by combining like terms.

1. Combine \(6y\) and \(-2y\):
\[
6y - 2y = 4y
\]

2. Combine \(-4\) and \(3\):
\[
-4 + 3 = -1
\]

Now, substitute these back into the equation:
\[
4y - 1 = 0
\]

3. Add \(1\) to both sides:
\[
4y = 1
\]

4. Divide by \(4\):
\[
y = \frac{1}{4}
\]

Thus, the solution to the equation is:
\[
y = \frac{1}{4}
\]