To evaluate \( \frac{4^{-2}}{7^{-2}} \), we can use the property of exponents that states \( a^{-n} = \frac{1}{a^n} \).
First, rewrite \( 4^{-2} \) and \( 7^{-2} \):
\[ 4^{-2} = \frac{1}{4^2} = \frac{1}{16} \]
\[ 7^{-2} = \frac{1}{7^2} = \frac{1}{49} \]
Now, substitute these into the original expression:
\[ \frac{4^{-2}}{7^{-2}} = \frac{\frac{1}{16}}{\frac{1}{49}} \]
Dividing by a fraction is the same as multiplying by its reciprocal:
\[ \frac{1}{16} \times \frac{49}{1} = \frac{49}{16} \]
Thus, the final answer is:
\[ \frac{49}{16} \]
And as a simplified fraction, it remains \( \frac{49}{16} \).