which of the following values for x makes the inequality sqrt 4x+1 ⪯ 5.83 true

1 answer

To solve the inequality \( \sqrt{4x + 1} \leq 5.83 \), we first square both sides (since both sides are non-negative):

\[ 4x + 1 \leq (5.83)^2 \]

Calculating \( (5.83)^2 \):

\[ (5.83)^2 = 33.9889 \]

Thus, the inequality becomes:

\[ 4x + 1 \leq 33.9889 \]

Next, we subtract 1 from both sides:

\[ 4x \leq 33.9889 - 1 \] \[ 4x \leq 32.9889 \]

Now, we divide both sides by 4:

\[ x \leq \frac{32.9889}{4} \] \[ x \leq 8.247225 \]

So, the solution to the inequality is:

\[ x \leq 8.247225 \]

Any value for \( x \) that is less than or equal to approximately 8.25 will make the inequality \( \sqrt{4x + 1} \leq 5.83 \) true.