Question

consider the following expression: -6 + 3 dot 5 ____ sqrt16 + 32 divided by 8
which operator can be inserted to make the statement true?

<
>
=
or ⪯

Answer 1

Let's break down the expression step by step:

1. **Evaluate the expression without an operator:**
- The given expression is:
\[ -6 + 3 \cdot 5 \quad \_\_\_ \quad \sqrt{16} + \frac{32}{8} \]

2. **Calculate each part:**
- Calculate \(3 \cdot 5\):
\[ 3 \cdot 5 = 15 \]
- So, the left side becomes:
\[ -6 + 15 = 9 \]

- Calculate \(\sqrt{16}\):
\[ \sqrt{16} = 4 \]
- Calculate \(\frac{32}{8}\):
\[ \frac{32}{8} = 4 \]
- Now, sum these values:
\[ 4 + 4 = 8 \]

3. **Now we have:**
\[ 9 \quad \_\_\_ \quad 8 \]

4. **Determine the appropriate operator:**
- We need to determine which operator makes the statement true between:
- \(<\)
- \(>\)
- \(=\)
- \(⪯\)

- Since \(9 > 8\), the appropriate operator to insert is \(>\).

So, the correct answer is:
**>**