To find the solution set of the inequalities \( 4x - 3 > 9 \) and \( x + 6 > -2 \), we'll solve each inequality separately.
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Solve the first inequality: \[ 4x - 3 > 9 \] Add 3 to both sides: \[ 4x > 12 \] Divide both sides by 4: \[ x > 3 \]
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Solve the second inequality: \[ x + 6 > -2 \] Subtract 6 from both sides: \[ x > -8 \]
Now we combine the results:
- From the first inequality, we have \( x > 3 \).
- From the second inequality, we have \( x > -8 \).
The solution set that satisfies both inequalities is the intersection of the two solutions: Since \( x > 3 \) is more restrictive than \( x > -8 \), the solution set is: \[ { x \mid x > 3 } \]
So, the correct response is: {x | x > 3}.