To express the solution to the equation \(3x^2 + 7 = 10\) in set notation, we first need to solve for \(x\).
Starting with the original equation:
\[ 3x^2 + 7 = 10 \]
Subtract 7 from both sides:
\[ 3x^2 = 3 \]
Now divide by 3:
\[ x^2 = 1 \]
Taking the square root of both sides gives:
\[ x = \pm 1 \]
Thus, the solutions are:
\[ x = -1 \quad \text{and} \quad x = 1 \]
In set notation, this can be expressed as:
\[ { -1, 1 } \]
So the final answer is:
\[ {-1, 1} \]