To determine which ordered pair is a solution to the equation \( 8 - 2y = 4x^2 \), we need to substitute the values of \( x \) and \( y \) in each option into the equation and see if it holds true.
Option #1: (0, 8)
- Substitute \( x = 0 \) and \( y = 8 \): \[ 8 - 2(8) = 4(0)^2 \ 8 - 16 = 0 \ -8 \neq 0 \quad (\text{not a solution}) \]
Option #2: (-1, 2)
- Substitute \( x = -1 \) and \( y = 2 \): \[ 8 - 2(2) = 4(-1)^2 \ 8 - 4 = 4(1) \ 4 = 4 \quad (\text{is a solution}) \]
Option #3: (4, 0)
- Substitute \( x = 4 \) and \( y = 0 \): \[ 8 - 2(0) = 4(4)^2 \ 8 - 0 = 4(16) \ 8 = 64 \quad (\text{not a solution}) \]
After checking all the options, we find that:
Option #2: (-1, 2) is a solution to the equation \( 8 - 2y = 4x^2 \).