Question
Use the chemical reaction to answer the question.
2H2+O2→2H2O
There are four atoms of hydrogen ( H
) before the reaction. How many atoms of hydrogen are present after the reaction?
2H2+O2→2H2O
There are four atoms of hydrogen ( H
) before the reaction. How many atoms of hydrogen are present after the reaction?
Answers
Answered by
GPT-4o mini
In the chemical reaction:
\[ 2H_2 + O_2 \rightarrow 2H_2O \]
We can break it down as follows:
- On the left side of the equation, there are 2 molecules of \( H_2 \), and each \( H_2 \) molecule contains 2 hydrogen atoms. Therefore, the total number of hydrogen atoms before the reaction is:
\[ 2 \, \text{molecules} \times 2 \, \text{atoms/molecule} = 4 \, \text{atoms of H} \]
- On the right side of the equation, there are 2 molecules of \( H_2O \), and each \( H_2O \) molecule contains 2 hydrogen atoms. Therefore, the total number of hydrogen atoms after the reaction is:
\[ 2 \, \text{molecules} \times 2 \, \text{atoms/molecule} = 4 \, \text{atoms of H} \]
Thus, there are 4 atoms of hydrogen present after the reaction as well. The number of hydrogen atoms remains the same before and after the reaction.
\[ 2H_2 + O_2 \rightarrow 2H_2O \]
We can break it down as follows:
- On the left side of the equation, there are 2 molecules of \( H_2 \), and each \( H_2 \) molecule contains 2 hydrogen atoms. Therefore, the total number of hydrogen atoms before the reaction is:
\[ 2 \, \text{molecules} \times 2 \, \text{atoms/molecule} = 4 \, \text{atoms of H} \]
- On the right side of the equation, there are 2 molecules of \( H_2O \), and each \( H_2O \) molecule contains 2 hydrogen atoms. Therefore, the total number of hydrogen atoms after the reaction is:
\[ 2 \, \text{molecules} \times 2 \, \text{atoms/molecule} = 4 \, \text{atoms of H} \]
Thus, there are 4 atoms of hydrogen present after the reaction as well. The number of hydrogen atoms remains the same before and after the reaction.
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