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Original Question
Apply the Product Rule of Exponents to form an equivalent expression of 1^6⋅1^2⋅1^1Asked by Evan and Max
Apply the Product Rule of Exponents to form an equivalent expression of 1^6⋅1^2⋅1^1
Answers
Answered by
Evan and Max
wrong pick one of these answers: 1^12 1^13 1^9 1^3
Answered by
GPT-4o mini
To apply the Product Rule of Exponents, we use the rule that states:
\[
a^m \cdot a^n = a^{m+n}
\]
In your case, we have the expression:
\[
1^6 \cdot 1^2 \cdot 1^1
\]
Since the base is the same (which is 1), we can add the exponents:
\[
1^{6+2+1} = 1^{9}
\]
Thus, the equivalent expression of \( 1^6 \cdot 1^2 \cdot 1^1 \) is:
\[
1^9
\]
And since any power of 1 is still 1, we can also say:
\[
1^{9} = 1
\]
So, the final result is:
\[
1
\]
\[
a^m \cdot a^n = a^{m+n}
\]
In your case, we have the expression:
\[
1^6 \cdot 1^2 \cdot 1^1
\]
Since the base is the same (which is 1), we can add the exponents:
\[
1^{6+2+1} = 1^{9}
\]
Thus, the equivalent expression of \( 1^6 \cdot 1^2 \cdot 1^1 \) is:
\[
1^9
\]
And since any power of 1 is still 1, we can also say:
\[
1^{9} = 1
\]
So, the final result is:
\[
1
\]
Answered by
GPT-4o mini
Let's evaluate the expression \( 1^6 \cdot 1^2 \cdot 1^1 \) again using the Product Rule of Exponents.
We add the exponents:
\[
1^6 \cdot 1^2 \cdot 1^1 = 1^{6+2+1} = 1^9
\]
So, among the choices you provided, the correct answer is:
\[
\boxed{1^9}
\]
We add the exponents:
\[
1^6 \cdot 1^2 \cdot 1^1 = 1^{6+2+1} = 1^9
\]
So, among the choices you provided, the correct answer is:
\[
\boxed{1^9}
\]