Question
What is the product of the polynomials (x2y+2)(x2−y) ?(1 point)
Responses
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
x3y−x2y2+2x2−2y
x cubed y minus x squared y squared plus 2 x squared minus 2 y
x4y−xy+x2y
x superscript 4 baseline y minus x y plus x squared y
x4y−x2y2+2x2−2y
x superscript 4 baseline y minus x squared y squared plus 2 x squared minus 2 y
ABC OR D
Responses
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
x3y−x2y2+2x2−2y
x cubed y minus x squared y squared plus 2 x squared minus 2 y
x4y−xy+x2y
x superscript 4 baseline y minus x y plus x squared y
x4y−x2y2+2x2−2y
x superscript 4 baseline y minus x squared y squared plus 2 x squared minus 2 y
ABC OR D
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we can use the distributive property (also known as the FOIL method for binomials).
Let's distribute each term in the first polynomial across the second polynomial:
1. **Multiply \(x^2y\) by each term in \((x^2 - y)\)**:
- \(x^2y \cdot x^2 = x^4y\)
- \(x^2y \cdot (-y) = -x^2y^2\)
2. **Multiply \(2\) by each term in \((x^2 - y)\)**:
- \(2 \cdot x^2 = 2x^2\)
- \(2 \cdot (-y) = -2y\)
Now, we can combine all these results:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
So the expanded form of \((x^2y + 2)(x^2 - y)\) is:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Looking at the responses you provided, the correct option is:
**x^4y - x^2y^2 + 2x^2 - 2y.**
Thus, the answer is:
**D.** x^4y − x^2y^2 + 2x^2 − 2y.
Let's distribute each term in the first polynomial across the second polynomial:
1. **Multiply \(x^2y\) by each term in \((x^2 - y)\)**:
- \(x^2y \cdot x^2 = x^4y\)
- \(x^2y \cdot (-y) = -x^2y^2\)
2. **Multiply \(2\) by each term in \((x^2 - y)\)**:
- \(2 \cdot x^2 = 2x^2\)
- \(2 \cdot (-y) = -2y\)
Now, we can combine all these results:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
So the expanded form of \((x^2y + 2)(x^2 - y)\) is:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Looking at the responses you provided, the correct option is:
**x^4y - x^2y^2 + 2x^2 - 2y.**
Thus, the answer is:
**D.** x^4y − x^2y^2 + 2x^2 − 2y.
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