Question

Three decimal places what is the hypotenuse of a right triangle that has height of 33’ and a base of 27’

Answer 1

To find the hypotenuse \( c \) of a right triangle with a height \( a = 33' \) and a base \( b = 27' \), we can use the Pythagorean theorem, which states:

\[
c = \sqrt{a^2 + b^2}
\]

Substituting the values:

\[
c = \sqrt{33^2 + 27^2}
\]

Calculating \( 33^2 \) and \( 27^2 \):

\[
33^2 = 1089
\]
\[
27^2 = 729
\]

Now, adding these two results:

\[
c = \sqrt{1089 + 729}
\]
\[
c = \sqrt{1818}
\]

Now, calculating \( \sqrt{1818} \):

\[
c \approx 42.6
\]

Rounding this to three decimal places, we have:

\[
c \approx 42.634
\]

Thus, the hypotenuse of the triangle is approximately **42.634 feet**.