Question

Use the equation y-5=x/3 to fill in the missing values in the table below

Answer 1

To fill in the missing values using the equation \( y - 5 = \frac{x}{3} \), we can rearrange the equation to solve for \( y \):

\[
y = \frac{x}{3} + 5
\]

Now, we can input various values for \(x\) to find the corresponding \(y\) values.

Please provide the values of \(x\) or the incomplete table you mentioned so that I can help fill in the missing values.

Answer 2

X y
_ 1
-3 4
0 _
6 _
_ 8

0,7,5,1,-12,12,9

Answer 3

Let's use the equation \( y - 5 = \frac{x}{3} \) or, equivalently, \( y = \frac{x}{3} + 5 \) to find the missing values for \(y\) based on the provided \(x\) values.

We will use the values you provided: \(0, 7, 5, 1, -12, 12, 9\) to find the matches.

### Filling Out the Table

1. **For \( x = \_ \), \( y = 1 \)**:
\[
1 = \frac{x}{3} + 5
\]
\[
\frac{x}{3} = 1 - 5 \Rightarrow \frac{x}{3} = -4 \Rightarrow x = -12
\]

2. **For \( x = -3 \), \( y = 4\)** (already given, for checking):
\[
4 = \frac{-3}{3} + 5 \Rightarrow 4 = -1 + 5 \Rightarrow \text{True}
\]

3. **For \( x = 0 \), \( y = \_ \)**:
\[
y = \frac{0}{3} + 5 = 5
\]

4. **For \( x = 6 \), \( y = \_ \)**:
\[
y = \frac{6}{3} + 5 = 2 + 5 = 7
\]

5. **For \( x = \_ \), \( y = 8 \)**:
\[
8 = \frac{x}{3} + 5
\]
\[
\frac{x}{3} = 8 - 5 \Rightarrow \frac{x}{3} = 3 \Rightarrow x = 9
\]

### Completed Table

Here’s the completed table with all the values filled in:

\[
\begin{array}{|c|c|}
\hline
X & Y \\
\hline
-12 & 1 \\
-3 & 4 \\
0 & 5 \\
6 & 7 \\
9 & 8 \\
\hline
\end{array}
\]

So the missing values are:

- For the first row: \( x = -12 \)
- For the third row: \( y = 5 \)
- For the fourth row: \( y = 7 \)
- For the last row: \( x = 9 \)

Let me know if you need any further assistance!

Answer 4

Are you positive

Answer 5

Let's carefully verify the calculations for the values in the table one more time using the equation \( y - 5 = \frac{x}{3} \) (or \( y = \frac{x}{3} + 5 \)).

### Given Table for Verification

| x | y |
|-----|-----|
| _ | 1 |
| -3 | 4 |
| 0 | _ |
| 6 | _ |
| _ | 8 |

### Step-by-Step Calculation

1. **For the first row where \( y = 1 \)**:
\[
1 = \frac{x}{3} + 5
\]
\[
\frac{x}{3} = 1 - 5 \Rightarrow \frac{x}{3} = -4 \Rightarrow x = -12
\]

2. **For the second row where \( x = -3 \)**:
\[
y = \frac{-3}{3} + 5 = -1 + 5 = 4 \quad (\text{This is correct.})
\]

3. **For the third row where \( x = 0 \)**:
\[
y = \frac{0}{3} + 5 = 5
\]

4. **For the fourth row where \( x = 6 \)**:
\[
y = \frac{6}{3} + 5 = 2 + 5 = 7
\]

5. **For the fifth row where \( y = 8 \)**:
\[
8 = \frac{x}{3} + 5
\]
\[
\frac{x}{3} = 8 - 5 \Rightarrow \frac{x}{3} = 3 \Rightarrow x = 9
\]

### Completed Table Verification

After double-checking the calculations, the values are confirmed as follows:

| x | y |
|-----|-----|
| -12 | 1 |
| -3 | 4 |
| 0 | 5 |
| 6 | 7 |
| 9 | 8 |

### Summary of Missing Values:
- For \( y = 1 \), \( x = -12 \)
- For \( x = 0 \), \( y = 5 \)
- For \( x = 6 \), \( y = 7 \)
- For \( y = 8 \), \( x = 9 \)

Based on these calculations, I can confirm that the previous answer is accurate. If you have additional concerns or would like to explore further, please let me know!