Question
Use the table of information to answer the question.
Fruit Mass (kg) Speed (m/s)
Watermelon A 4 2
Watermelon B 4 4
Two watermelons fall off a kitchen counter. The masses and speeds of the fruits are in the table. How do the kinetic and/or the potential energies of the fruits compare?(1 point)
Responses
The watermelon B has more kinetic energy.
The watermelon B has more kinetic energy.
Both fruits have the same kinetic and potential energy.
Both fruits have the same kinetic and potential energy.
The watermelon A has more kinetic energy.
The watermelon A has more kinetic energy.
Both fruits have only potential energy and no kinetic energy.
Fruit Mass (kg) Speed (m/s)
Watermelon A 4 2
Watermelon B 4 4
Two watermelons fall off a kitchen counter. The masses and speeds of the fruits are in the table. How do the kinetic and/or the potential energies of the fruits compare?(1 point)
Responses
The watermelon B has more kinetic energy.
The watermelon B has more kinetic energy.
Both fruits have the same kinetic and potential energy.
Both fruits have the same kinetic and potential energy.
The watermelon A has more kinetic energy.
The watermelon A has more kinetic energy.
Both fruits have only potential energy and no kinetic energy.
Answers
GPT-4o mini
To compare the kinetic energies of the two watermelons, we can use the formula for kinetic energy:
\[ KE = \frac{1}{2}mv^2 \]
where \( m \) is the mass and \( v \) is the speed.
For Watermelon A:
- Mass \( m_A = 4 \) kg
- Speed \( v_A = 2 \) m/s
\[ KE_A = \frac{1}{2} \times 4 \times (2^2) = \frac{1}{2} \times 4 \times 4 = 8 \, \text{J} \]
For Watermelon B:
- Mass \( m_B = 4 \) kg
- Speed \( v_B = 4 \) m/s
\[ KE_B = \frac{1}{2} \times 4 \times (4^2) = \frac{1}{2} \times 4 \times 16 = 32 \, \text{J} \]
Now we can compare the kinetic energies:
- \( KE_A = 8 \, \text{J} \)
- \( KE_B = 32 \, \text{J} \)
Watermelon B has more kinetic energy than Watermelon A.
So the correct response is:
**The watermelon B has more kinetic energy.**
\[ KE = \frac{1}{2}mv^2 \]
where \( m \) is the mass and \( v \) is the speed.
For Watermelon A:
- Mass \( m_A = 4 \) kg
- Speed \( v_A = 2 \) m/s
\[ KE_A = \frac{1}{2} \times 4 \times (2^2) = \frac{1}{2} \times 4 \times 4 = 8 \, \text{J} \]
For Watermelon B:
- Mass \( m_B = 4 \) kg
- Speed \( v_B = 4 \) m/s
\[ KE_B = \frac{1}{2} \times 4 \times (4^2) = \frac{1}{2} \times 4 \times 16 = 32 \, \text{J} \]
Now we can compare the kinetic energies:
- \( KE_A = 8 \, \text{J} \)
- \( KE_B = 32 \, \text{J} \)
Watermelon B has more kinetic energy than Watermelon A.
So the correct response is:
**The watermelon B has more kinetic energy.**