Question
At the time of her grandson's birth, a grandmother deposits $1000 in an account that pays 2% compounded monthly. What will be the value of the account at the child's twenty-first birthday, assuming that no other deposits or withdrawals are made during this period?
The value of the account will be
The value of the account will be
Answers
GPT-4o mini
To calculate the future value of the account at the child's twenty-first birthday, we'll use the formula for compound interest:
\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]
Where:
- \( A \) = the future value of the investment/loan, including interest
- \( P \) = the principal investment amount (the initial deposit or loan amount) = $1000
- \( r \) = the annual interest rate (decimal) = 2% = 0.02
- \( n \) = the number of times that interest is compounded per year = 12 (monthly)
- \( t \) = the number of years the money is invested or borrowed for = 21 years
Now let’s plug in the values into the formula:
\[
A = 1000 \left(1 + \frac{0.02}{12}\right)^{12 \times 21}
\]
Calculating \( \frac{0.02}{12} \):
\[
\frac{0.02}{12} = 0.00166667
\]
Now substitute this back into the formula:
\[
A = 1000 \left(1 + 0.00166667\right)^{12 \times 21}
\]
Calculating \( 12 \times 21 \):
\[
12 \times 21 = 252
\]
So now we have:
\[
A = 1000 \left(1.00166667\right)^{252}
\]
Next, we can calculate \( \left(1.00166667\right)^{252} \):
Using a calculator:
\[
1.00166667^{252} \approx 1.490665
\]
Finally, we multiply this by the principal amount:
\[
A \approx 1000 \times 1.490665 \approx 1490.67
\]
Thus, the value of the account at the child's twenty-first birthday will be approximately **$1490.67**.
\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]
Where:
- \( A \) = the future value of the investment/loan, including interest
- \( P \) = the principal investment amount (the initial deposit or loan amount) = $1000
- \( r \) = the annual interest rate (decimal) = 2% = 0.02
- \( n \) = the number of times that interest is compounded per year = 12 (monthly)
- \( t \) = the number of years the money is invested or borrowed for = 21 years
Now let’s plug in the values into the formula:
\[
A = 1000 \left(1 + \frac{0.02}{12}\right)^{12 \times 21}
\]
Calculating \( \frac{0.02}{12} \):
\[
\frac{0.02}{12} = 0.00166667
\]
Now substitute this back into the formula:
\[
A = 1000 \left(1 + 0.00166667\right)^{12 \times 21}
\]
Calculating \( 12 \times 21 \):
\[
12 \times 21 = 252
\]
So now we have:
\[
A = 1000 \left(1.00166667\right)^{252}
\]
Next, we can calculate \( \left(1.00166667\right)^{252} \):
Using a calculator:
\[
1.00166667^{252} \approx 1.490665
\]
Finally, we multiply this by the principal amount:
\[
A \approx 1000 \times 1.490665 \approx 1490.67
\]
Thus, the value of the account at the child's twenty-first birthday will be approximately **$1490.67**.