15 = 10x + 5y

x -2 -1 0 2 3
y

1 answer

To find the values of \( y \) for the equation \( 15 = 10x + 5y \) given the values for \( x \) as \(-2, -1, 0, 2, 3\), we'll substitute each value of \( x \) into the equation and solve for \( y \).

Step 1: Solve the equation for \( y \)

Starting from the original equation: \[ 15 = 10x + 5y \]

Rearranging it gives: \[ 5y = 15 - 10x \] \[ y = \frac{15 - 10x}{5} \] \[ y = 3 - 2x \]

Step 2: Calculate \( y \) for each value of \( x \)

  1. When \( x = -2 \): \[ y = 3 - 2(-2) = 3 + 4 = 7 \]

  2. When \( x = -1 \): \[ y = 3 - 2(-1) = 3 + 2 = 5 \]

  3. When \( x = 0 \): \[ y = 3 - 2(0) = 3 - 0 = 3 \]

  4. When \( x = 2 \): \[ y = 3 - 2(2) = 3 - 4 = -1 \]

  5. When \( x = 3 \): \[ y = 3 - 2(3) = 3 - 6 = -3 \]

Summary of \( y \) values

  • For \( x = -2 \), \( y = 7 \)
  • For \( x = -1 \), \( y = 5 \)
  • For \( x = 0 \), \( y = 3 \)
  • For \( x = 2 \), \( y = -1 \)
  • For \( x = 3 \), \( y = -3 \)

Here is a summary of the results:

\[ \begin{align*} x & : -2, -1, 0, 2, 3 \ y & : 7, 5, 3, -1, -3 \ \end{align*} \]