Asked by Scar
An equation is shown. 3x2−8x+4=0
. Complete the statements.(3 points)
The value of a is
3
.
The value of b is
-8
.
The value of c is
4
.
Question 2
9. Using the quadratic equation above, fill in for a, b, and c. (3 points)
-8
-8
3
4
3
Question 3
10. What is one solution of the above quadratic equation?(1 point)
Responses
(1,-1)
(1,-1)
(-0.67,0)
(-0.67,0)
(0,4)
(0,4)
(2,0)
(2,0)
. Complete the statements.(3 points)
The value of a is
3
.
The value of b is
-8
.
The value of c is
4
.
Question 2
9. Using the quadratic equation above, fill in for a, b, and c. (3 points)
-8
-8
3
4
3
Question 3
10. What is one solution of the above quadratic equation?(1 point)
Responses
(1,-1)
(1,-1)
(-0.67,0)
(-0.67,0)
(0,4)
(0,4)
(2,0)
(2,0)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the quadratic equation \(3x^2 - 8x + 4 = 0\), we can use the quadratic formula:
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
We already identified the values of \(a\), \(b\), and \(c\):
- The value of \(a\) is \(3\).
- The value of \(b\) is \(-8\).
- The value of \(c\) is \(4\).
Substituting these values into the quadratic formula:
1. Calculate the discriminant:
\[
b^2 - 4ac = (-8)^2 - 4(3)(4) = 64 - 48 = 16
\]
2. Substitute into the quadratic formula:
\[
x = \frac{-(-8) \pm \sqrt{16}}{2(3)}
\]
\[
x = \frac{8 \pm 4}{6}
\]
3. Calculate the two possible solutions:
- First solution:
\[
x = \frac{8 + 4}{6} = \frac{12}{6} = 2
\]
- Second solution:
\[
x = \frac{8 - 4}{6} = \frac{4}{6} = \frac{2}{3} \approx 0.67
\]
Now, looking at the given response options for Question 3, the solutions would be:
- The solution \( (2, 0) \) corresponds to \(x = 2\).
- The solution \( (-0.67, 0) \) corresponds to \(x \approx 0.67\), which is not an exact match but is close.
Since \(2\) is one of the values we calculated from the equation, the answer to Question 3 is:
**(2, 0)**.
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
We already identified the values of \(a\), \(b\), and \(c\):
- The value of \(a\) is \(3\).
- The value of \(b\) is \(-8\).
- The value of \(c\) is \(4\).
Substituting these values into the quadratic formula:
1. Calculate the discriminant:
\[
b^2 - 4ac = (-8)^2 - 4(3)(4) = 64 - 48 = 16
\]
2. Substitute into the quadratic formula:
\[
x = \frac{-(-8) \pm \sqrt{16}}{2(3)}
\]
\[
x = \frac{8 \pm 4}{6}
\]
3. Calculate the two possible solutions:
- First solution:
\[
x = \frac{8 + 4}{6} = \frac{12}{6} = 2
\]
- Second solution:
\[
x = \frac{8 - 4}{6} = \frac{4}{6} = \frac{2}{3} \approx 0.67
\]
Now, looking at the given response options for Question 3, the solutions would be:
- The solution \( (2, 0) \) corresponds to \(x = 2\).
- The solution \( (-0.67, 0) \) corresponds to \(x \approx 0.67\), which is not an exact match but is close.
Since \(2\) is one of the values we calculated from the equation, the answer to Question 3 is:
**(2, 0)**.
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