Use the equation of motion to answer the question.

Question

x=x0+v0t+12at2
An object has a starting position of x = 2 m, a starting velocity of 4.5 m/s, and no acceleration. Which option shows the final position of the object after 2 s?

(1 point)
Responses

5.5 m
5.5 m

18 m
18 m

9 m
9 m

11 m

Answer 1

To find the final position $x$ of the object after 2 seconds using the equation of motion:

$$x=x_0+v_{0}t+\frac{1}{2}a{t}^2$$

Given:

• Initial position $x_0=2$ m
• Initial velocity $v_0=4.5$ m/s
• Acceleration $a=0$ (since there is no acceleration)
• Time $t=2$ s

We can plug in the values into the equation:

$$x=2+4.5\cdot 2+\frac{1}{2}\cdot 0\cdot (2^2)$$

Calculating this step-by-step:

1. Calculate $4.5\cdot 2$: $$4.5\cdot 2=9$$

2. Since the acceleration is 0, the term $\frac{1}{2}\cdot 0\cdot (2^2)=0$.

3. Now substitute these values back into the equation: $$x=2+9+0$$ $$x=11,\text{m}$$

Therefore, the final position of the object after 2 seconds is 11 m.

The correct response is 11 m.