To find the final position \( x \) of the object after 2 seconds using the equation of motion:
\[ x = x_0 + v_0 t + \frac{1}{2} a t^2 \]
Given:
- Initial position \( x_0 = 2 \) m
- Initial velocity \( v_0 = 4.5 \) m/s
- Acceleration \( a = 0 \) (since there is no acceleration)
- Time \( t = 2 \) s
We can plug in the values into the equation:
\[ x = 2 + 4.5 \cdot 2 + \frac{1}{2} \cdot 0 \cdot (2^2) \]
Calculating this step-by-step:
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Calculate \( 4.5 \cdot 2 \): \[ 4.5 \cdot 2 = 9 \]
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Since the acceleration is 0, the term \( \frac{1}{2} \cdot 0 \cdot (2^2) = 0 \).
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Now substitute these values back into the equation: \[ x = 2 + 9 + 0 \] \[ x = 11 , \text{m} \]
Therefore, the final position of the object after 2 seconds is 11 m.
The correct response is 11 m.