A water tank decreases by 10 gallons every 3 hours every day. What is the total change in the amount of water in the tank after 6 days?(1 point)

To find the total change in the amount of water in the tank after 6 days, we first calculate how much the tank decreases in one day.

The tank decreases by 10 gallons every 3 hours. There are 24 hours in a day, so we can calculate the number of 3-hour periods in one day:

\[
\text{Number of 3-hour periods in one day} = \frac{24 \text{ hours}}{3 \text{ hours/period}} = 8 \text{ periods}
\]

Next, we find the total decrease in gallons for one day:

\[
\text{Decrease per day} = 10 \text{ gallons/period} \times 8 \text{ periods} = 80 \text{ gallons}
\]

Now, to find the total decrease over 6 days:

\[
\text{Total decrease after 6 days} = 80 \text{ gallons/day} \times 6 \text{ days} = 480 \text{ gallons}
\]

Since the tank is decreasing in water, we express our answer as a negative change:

\[
\text{Total change} = -480 \text{ gallons}
\]

Thus, the final answer is:

**−480 gallons**.