Question

f(x) = 1/2x+3 with inputs of -4,-2,0,2 and 4

Answer 1

To evaluate the function \( f(x) = \frac{1}{2}x + 3 \) for the inputs -4, -2, 0, 2, and 4, we will substitute each input into the function and calculate the corresponding output.

1. **For \( x = -4 \)**:
\[
f(-4) = \frac{1}{2}(-4) + 3 = -2 + 3 = 1
\]

2. **For \( x = -2 \)**:
\[
f(-2) = \frac{1}{2}(-2) + 3 = -1 + 3 = 2
\]

3. **For \( x = 0 \)**:
\[
f(0) = \frac{1}{2}(0) + 3 = 0 + 3 = 3
\]

4. **For \( x = 2 \)**:
\[
f(2) = \frac{1}{2}(2) + 3 = 1 + 3 = 4
\]

5. **For \( x = 4 \)**:
\[
f(4) = \frac{1}{2}(4) + 3 = 2 + 3 = 5
\]

Now, let's summarize the results:

- \( f(-4) = 1 \)
- \( f(-2) = 2 \)
- \( f(0) = 3 \)
- \( f(2) = 4 \)
- \( f(4) = 5 \)

Thus, the outputs for the function \( f(x) \) at the specified inputs are:

\[
\begin{align*}
f(-4) & = 1 \\
f(-2) & = 2 \\
f(0) & = 3 \\
f(2) & = 4 \\
f(4) & = 5 \\
\end{align*}
\]