Asked by JOTHEY
Two 2.5-cm-diameter electrodes with a 0.10-mm-thick sheet of Teflon between them are attached to a 9.0V battery. Without disconnecting the battery, the Teflon is removed.
a) What is the charge before the Teflon is removed? Q= C
b) What is the potential difference before the Teflon is removed? V= V
c) What is the electric field before the Teflon is removed? E= V/m
d) What is the charge after the Teflon is removed? Q= C
e) What is the potential difference after the Teflon is removed? V= V
f) What are the electric field after the Teflon is removed?
a) What is the charge before the Teflon is removed? Q= C
b) What is the potential difference before the Teflon is removed? V= V
c) What is the electric field before the Teflon is removed? E= V/m
d) What is the charge after the Teflon is removed? Q= C
e) What is the potential difference after the Teflon is removed? V= V
f) What are the electric field after the Teflon is removed?
Answers
Answered by
Damon
a) What is the charge before the Teflon is removed? Q= C
NO
Q = C V
same in part d
The field E is 9 Volts/(10^-4 mters)
with or without teflon
However C depends on the material
NO
Q = C V
same in part d
The field E is 9 Volts/(10^-4 mters)
with or without teflon
However C depends on the material
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