Question

f(x)=2x+11 using inputs of -29, -10, 0, 10, and 20

Answer 1

To evaluate the function \( f(x) = 2x + 11 \) for the inputs \( x = -29, -10, 0, 10, \) and \( 20 \), we simply substitute each value of \( x \) into the function.

1. For \( x = -29 \):
\[
f(-29) = 2(-29) + 11 = -58 + 11 = -47
\]

2. For \( x = -10 \):
\[
f(-10) = 2(-10) + 11 = -20 + 11 = -9
\]

3. For \( x = 0 \):
\[
f(0) = 2(0) + 11 = 0 + 11 = 11
\]

4. For \( x = 10 \):
\[
f(10) = 2(10) + 11 = 20 + 11 = 31
\]

5. For \( x = 20 \):
\[
f(20) = 2(20) + 11 = 40 + 11 = 51
\]

Now, summarizing the results:

- \( f(-29) = -47 \)
- \( f(-10) = -9 \)
- \( f(0) = 11 \)
- \( f(10) = 31 \)
- \( f(20) = 51 \)

Therefore, the values of \( f(x) \) for the given inputs are:
- \( f(-29) = -47 \)
- \( f(-10) = -9 \)
- \( f(0) = 11 \)
- \( f(10) = 31 \)
- \( f(20) = 51 \)