Question
Write the polynomial expression in simplest form: 2x^2−32/x−4 ⋅ 10x+20/5x^2−20
A. 4
B. 4(x+4)/x−2
C. 20(x+4)5(x−2)
D. 4(x+4)/x+2
A. 4
B. 4(x+4)/x−2
C. 20(x+4)5(x−2)
D. 4(x+4)/x+2
Answers
GPT-4o mini
To simplify the expression \( \frac{2x^2 - 32}{x - 4} \cdot \frac{10x + 20}{5x^2 - 20} \), we'll start by factoring where possible.
1. **Factor \( 2x^2 - 32 \)**:
\[
2x^2 - 32 = 2(x^2 - 16) = 2(x - 4)(x + 4)
\]
2. **Factor \( 10x + 20 \)**:
\[
10x + 20 = 10(x + 2)
\]
3. **Factor \( 5x^2 - 20 \)**:
\[
5x^2 - 20 = 5(x^2 - 4) = 5(x - 2)(x + 2)
\]
Now, we can rewrite the original expression using these factors:
\[
\frac{2(x - 4)(x + 4)}{x - 4} \cdot \frac{10(x + 2)}{5(x - 2)(x + 2)}
\]
Next, simplify the expression:
- The \( x - 4 \) in the numerator and denominator cancels out:
\[
= 2(x + 4) \cdot \frac{10(x + 2)}{5(x - 2)(x + 2)}
\]
The \( x + 2 \) in the numerator and denominator also cancels out:
\[
= 2(x + 4) \cdot \frac{10}{5(x - 2)}
\]
Now, simplify \( \frac{10}{5} = 2 \):
\[
= 2(x + 4) \cdot \frac{2}{(x - 2)} = \frac{4(x + 4)}{(x - 2)}
\]
Thus, the simplest form of the polynomial expression is:
\[
\frac{4(x + 4)}{x - 2}
\]
The correct answer is:
**B. \( \frac{4(x+4)}{x-2} \)**.
1. **Factor \( 2x^2 - 32 \)**:
\[
2x^2 - 32 = 2(x^2 - 16) = 2(x - 4)(x + 4)
\]
2. **Factor \( 10x + 20 \)**:
\[
10x + 20 = 10(x + 2)
\]
3. **Factor \( 5x^2 - 20 \)**:
\[
5x^2 - 20 = 5(x^2 - 4) = 5(x - 2)(x + 2)
\]
Now, we can rewrite the original expression using these factors:
\[
\frac{2(x - 4)(x + 4)}{x - 4} \cdot \frac{10(x + 2)}{5(x - 2)(x + 2)}
\]
Next, simplify the expression:
- The \( x - 4 \) in the numerator and denominator cancels out:
\[
= 2(x + 4) \cdot \frac{10(x + 2)}{5(x - 2)(x + 2)}
\]
The \( x + 2 \) in the numerator and denominator also cancels out:
\[
= 2(x + 4) \cdot \frac{10}{5(x - 2)}
\]
Now, simplify \( \frac{10}{5} = 2 \):
\[
= 2(x + 4) \cdot \frac{2}{(x - 2)} = \frac{4(x + 4)}{(x - 2)}
\]
Thus, the simplest form of the polynomial expression is:
\[
\frac{4(x + 4)}{x - 2}
\]
The correct answer is:
**B. \( \frac{4(x+4)}{x-2} \)**.