Question
efficient and generalizable procedures.
Answer: 0
Describe this as a 7th grader simplify it so it can fit in a small text box
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Answer
Describe real-world contexts Which context describes a difference of rational numbers? EX: A football player loses yards on a play. using differences of rational Your example: Do not use the same words from the EX.
numbers.
Describe this as a 7th grader simplify it so it can fit in a small text box
Answer
Joey walked east for 15 2/3 meters from home. Then, he walked west for 21 3/4 meters. How far was Joey from home? Write your answer as a mixed number only.
Describe this as a 7th grader simplify it so it can fit in a small text box
Answer
the answer to the problem is 6/12. explain how to get it.
Answer
simplify the answer as a 7th grader and make it so it can easily fit in a small text box
Answer
you wrote 73/12 isntead of 6 1/12
Answered by
GPT-4o mini
Efficient and generalizable procedures are steps that help us solve problems quickly and can be used in many situations. They are like shortcuts that work in different places, making life easier!
Answered by
GPT-4o mini
A hiker climbs up a mountain and then goes back down. The difference in height shows how many feet they went up or down, which can be described using positive and negative numbers.
Answered by
GPT-4o mini
Joey walked 15 2/3 meters east and then 21 3/4 meters west. To find out how far he is from home, we subtract the distance he walked east from the distance he walked west.
First, convert the mixed numbers:
- 15 2/3 = 15.67
- 21 3/4 = 21.75
Then, subtract:
21.75 - 15.67 = 6.08 or 6 2/25.
So, Joey is 6 2/25 meters away from home.
First, convert the mixed numbers:
- 15 2/3 = 15.67
- 21 3/4 = 21.75
Then, subtract:
21.75 - 15.67 = 6.08 or 6 2/25.
So, Joey is 6 2/25 meters away from home.
Answered by
GPT-4o mini
To find how far Joey is from home, we need to subtract the distance he walked east from the distance he walked west. Here's how to do it step by step:
1. **Convert mixed numbers to improper fractions:**
- **15 2/3** can be converted to an improper fraction:
\[
15 \times 3 + 2 = 45 + 2 = 47/3
\]
- **21 3/4** can also be converted:
\[
21 \times 4 + 3 = 84 + 3 = 87/4
\]
2. **Find a common denominator:**
The least common denominator for 3 and 4 is 12.
- Convert **47/3** to a denominator of 12:
\[
47/3 = 47 \times 4 / 3 \times 4 = 188/12
\]
- Convert **87/4** to a denominator of 12:
\[
87/4 = 87 \times 3 / 4 \times 3 = 261/12
\]
3. **Subtract the fractions:**
Now that we have a common denominator, we can subtract:
\[
261/12 - 188/12 = (261 - 188)/12 = 73/12
\]
4. **Interpret the result:**
Since Joey walked farther west than east, he is 73/12 meters from home. We can simplify 73/12 to a mixed number:
- \( 73 \div 12 = 6 \) with a remainder of \( 1 \), so it's \( 6 \frac{1}{12} \).
So, Joey is \( 6 \frac{1}{12} \) meters away from home, not \( 6/12 \). If your original answer was to be 6/12, that can be simplified to 1/2, which represents how far back towards home he ended up walking, but since you asked for the distance from home, the answer is \( 6 \frac{1}{12} \) meters.
1. **Convert mixed numbers to improper fractions:**
- **15 2/3** can be converted to an improper fraction:
\[
15 \times 3 + 2 = 45 + 2 = 47/3
\]
- **21 3/4** can also be converted:
\[
21 \times 4 + 3 = 84 + 3 = 87/4
\]
2. **Find a common denominator:**
The least common denominator for 3 and 4 is 12.
- Convert **47/3** to a denominator of 12:
\[
47/3 = 47 \times 4 / 3 \times 4 = 188/12
\]
- Convert **87/4** to a denominator of 12:
\[
87/4 = 87 \times 3 / 4 \times 3 = 261/12
\]
3. **Subtract the fractions:**
Now that we have a common denominator, we can subtract:
\[
261/12 - 188/12 = (261 - 188)/12 = 73/12
\]
4. **Interpret the result:**
Since Joey walked farther west than east, he is 73/12 meters from home. We can simplify 73/12 to a mixed number:
- \( 73 \div 12 = 6 \) with a remainder of \( 1 \), so it's \( 6 \frac{1}{12} \).
So, Joey is \( 6 \frac{1}{12} \) meters away from home, not \( 6/12 \). If your original answer was to be 6/12, that can be simplified to 1/2, which represents how far back towards home he ended up walking, but since you asked for the distance from home, the answer is \( 6 \frac{1}{12} \) meters.
Answered by
GPT-4o mini
Joey walked 15 2/3 meters east and then 21 3/4 meters west. To find out how far he is from home:
1. Change to improper fractions:
- 15 2/3 = 47/3
- 21 3/4 = 87/4
2. Get a common denominator (12):
- 47/3 = 188/12
- 87/4 = 261/12
3. Subtract:
- 261/12 - 188/12 = 73/12
Joey is 6 1/12 meters away from home!
1. Change to improper fractions:
- 15 2/3 = 47/3
- 21 3/4 = 87/4
2. Get a common denominator (12):
- 47/3 = 188/12
- 87/4 = 261/12
3. Subtract:
- 261/12 - 188/12 = 73/12
Joey is 6 1/12 meters away from home!
Answered by
GPT-4o mini
I see what you're asking for. Here’s a simplified response focused on the final answer:
---
Joey walked 15 2/3 meters east and 21 3/4 meters west.
1. Convert to improper fractions:
- 15 2/3 = 47/3
- 21 3/4 = 87/4
2. Find a common denominator (12):
- 47/3 = 188/12
- 87/4 = 261/12
3. Subtract:
- 261/12 - 188/12 = 73/12
This simplifies to 6 1/12 meters.
So, Joey is **6 1/12 meters** away from home!
---
Joey walked 15 2/3 meters east and 21 3/4 meters west.
1. Convert to improper fractions:
- 15 2/3 = 47/3
- 21 3/4 = 87/4
2. Find a common denominator (12):
- 47/3 = 188/12
- 87/4 = 261/12
3. Subtract:
- 261/12 - 188/12 = 73/12
This simplifies to 6 1/12 meters.
So, Joey is **6 1/12 meters** away from home!
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