Question
Use a graphing utility as an aid in factoring to solve the equation.
3xsquaredplus14xminus49equals0
Question content area bottom left
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your answer.
A.
The solution(s) is/are
enter your response here.
(Type an integer or a simplified fraction. Use a comma to separate answers as needed.)
B.
The equation has no solution.
3xsquaredplus14xminus49equals0
Question content area bottom left
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your answer.
A.
The solution(s) is/are
enter your response here.
(Type an integer or a simplified fraction. Use a comma to separate answers as needed.)
B.
The equation has no solution.
Answers
Answered by
GPT-4o mini
To solve the equation \(3x^2 + 14x - 49 = 0\), we can start by identifying the coefficients and then use the quadratic formula or a graphing utility to solve for \(x\).
The coefficients are:
- \(a = 3\)
- \(b = 14\)
- \(c = -49\)
### Step 1: Finding the Discriminant
The discriminant \((D)\) of a quadratic equation \(ax^2 + bx + c = 0\) is given by:
\[ D = b^2 - 4ac \]
Calculating the discriminant:
\[ D = 14^2 - 4(3)(-49) \]
\[ D = 196 + 588 \]
\[ D = 784 \]
Since the discriminant is positive, this means there are two real and distinct solutions.
### Step 2: Using the Quadratic Formula
The solutions can be found using the quadratic formula:
\[ x = \frac{-b \pm \sqrt{D}}{2a} \]
Substituting the values:
\[ x = \frac{-14 \pm \sqrt{784}}{2 \cdot 3} \]
\[ x = \frac{-14 \pm 28}{6} \]
### Step 3: Calculating the Two Solutions
1. **First Solution:**
\[ x = \frac{-14 + 28}{6} = \frac{14}{6} = \frac{7}{3} \]
2. **Second Solution:**
\[ x = \frac{-14 - 28}{6} = \frac{-42}{6} = -7 \]
### Final Answers
The solutions to the equation \(3x^2 + 14x - 49 = 0\) are:
- \(x = \frac{7}{3}\)
- \(x = -7\)
Thus, the answer is:
**A. The solutions are \(\frac{7}{3}, -7\).**
The coefficients are:
- \(a = 3\)
- \(b = 14\)
- \(c = -49\)
### Step 1: Finding the Discriminant
The discriminant \((D)\) of a quadratic equation \(ax^2 + bx + c = 0\) is given by:
\[ D = b^2 - 4ac \]
Calculating the discriminant:
\[ D = 14^2 - 4(3)(-49) \]
\[ D = 196 + 588 \]
\[ D = 784 \]
Since the discriminant is positive, this means there are two real and distinct solutions.
### Step 2: Using the Quadratic Formula
The solutions can be found using the quadratic formula:
\[ x = \frac{-b \pm \sqrt{D}}{2a} \]
Substituting the values:
\[ x = \frac{-14 \pm \sqrt{784}}{2 \cdot 3} \]
\[ x = \frac{-14 \pm 28}{6} \]
### Step 3: Calculating the Two Solutions
1. **First Solution:**
\[ x = \frac{-14 + 28}{6} = \frac{14}{6} = \frac{7}{3} \]
2. **Second Solution:**
\[ x = \frac{-14 - 28}{6} = \frac{-42}{6} = -7 \]
### Final Answers
The solutions to the equation \(3x^2 + 14x - 49 = 0\) are:
- \(x = \frac{7}{3}\)
- \(x = -7\)
Thus, the answer is:
**A. The solutions are \(\frac{7}{3}, -7\).**