Consider the expression x+6/3^2-(2•3)+5 what is simplified denominator

Answer 1

To simplify the expression $x+\frac{6}{3^2}-(2\cdot 3)+5$, we can evaluate the expression step-by-step.

1. Calculate $3^2$: $$3^2=9$$

2. Substitute this back into the expression: $$x+\frac{6}{9}-(2\cdot 3)+5$$

3. Simplify $\frac{6}{9}$: $$\frac{6}{9}=\frac{2}{3}$$

4. Calculate $2\cdot 3$: $$2\cdot 3=6$$

5. Substitute this back into the expression: $$x+\frac{2}{3}-6+5$$

6. Combine the constants $-6+5$: $$-6+5=-1$$

7. Substitute this back in: $$x+\frac{2}{3}-1$$

Now the expression can be rewritten as: $$x-1+\frac{2}{3}$$

To have a single fraction, we can express $-1$ as $-\frac{3}{3}$: $$x-\frac{3}{3}+\frac{2}{3}=x-\frac{3-2}{3}=x-\frac{1}{3}$$

Thus, the final simplified expression is: $$x-\frac{1}{3}$$

The simplified denominator involved in the original expression was $9$ (from $3^2$) and in the fraction, it is $3$ (from $\frac{2}{3}$).