To simplify the expression \( x + \frac{6}{3^2} - (2 \cdot 3) + 5 \), we can evaluate the expression step-by-step.
1. Calculate \( 3^2 \):
\[
3^2 = 9
\]
2. Substitute this back into the expression:
\[
x + \frac{6}{9} - (2 \cdot 3) + 5
\]
3. Simplify \( \frac{6}{9} \):
\[
\frac{6}{9} = \frac{2}{3}
\]
4. Calculate \( 2 \cdot 3 \):
\[
2 \cdot 3 = 6
\]
5. Substitute this back into the expression:
\[
x + \frac{2}{3} - 6 + 5
\]
6. Combine the constants \( -6 + 5 \):
\[
-6 + 5 = -1
\]
7. Substitute this back in:
\[
x + \frac{2}{3} - 1
\]
Now the expression can be rewritten as:
\[
x - 1 + \frac{2}{3}
\]
To have a single fraction, we can express \(-1\) as \(-\frac{3}{3}\):
\[
x - \frac{3}{3} + \frac{2}{3} = x - \frac{3 - 2}{3} = x - \frac{1}{3}
\]
Thus, the final simplified expression is:
\[
x - \frac{1}{3}
\]
The simplified denominator involved in the original expression was \(9\) (from \(3^2\)) and in the fraction, it is \(3\) (from \(\frac{2}{3}\)).