Let's go through each question one by one.
Question 1: Direction of Travel
- The blue ball is moving at a speed of 3 m/s (to the right if we assume the positive direction is to the right).
- The green ball is moving at a speed of -2 m/s (to the left, since negative indicates the opposite direction).
Answer: In opposite directions, towards each other.
Question 2: Momentum Before Collision
Momentum is calculated using the formula:
\[ \text{Momentum} = \text{mass} \times \text{velocity} \]
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For the blue ball: \[ \text{Momentum}_{\text{blue}} = 0.15 , \text{kg} \times 3 , \text{m/s} = 0.45 , \text{kg m/s} \]
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For the green ball: \[ \text{Momentum}_{\text{green}} = 0.15 , \text{kg} \times (-2 , \text{m/s}) = -0.3 , \text{kg m/s} \]
Answer: 0.45 kg.m/s ; -0.3 kg.m/s
Question 3: Total Momentum of Blue Ball After Collision
If the blue ball stays in place after the collision, its velocity is 0 m/s.
Using the momentum formula: \[ \text{Momentum}_{\text{blue}} = 0.15 , \text{kg} \times 0 , \text{m/s} = 0 , \text{kg m/s} \]
Answer: 0 kg.m/s
Question 4: Momentum and Direction of the Green Ball After Collision
If the blue ball stays in place and the green ball continues in motion, we need to determine the momentum of the green ball given it retains its speed of -2 m/s (the same as before since momentum is conserved).
Using the momentum formula: \[ \text{Momentum}_{\text{green}} = 0.15 , \text{kg} \times (-2 , \text{m/s}) = -0.3 , \text{kg m/s} \]
Since momentum is -0.3 kg m/s, which indicates movement in the direction opposite to its initial direction (the original travel direction was left), it would mean it is traveling left post-collision.
Answer: 0.3 kg.m/s straight ahead (taking 'straight ahead’ as the reverse direction given the scenario).
Feel free to ask if you have more questions or need further clarification!