A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2

Question

by using the formula 75−16t2
, where t
is time in seconds. (1 point)

Answer 1

To find the height of the diver above the ocean at \( t = 2 \) seconds using the formula:

\[ h(t) = 75 - 16t^2 \]

we can substitute \( t = 2 \) into the equation.

\[ h(2) = 75 - 16(2^2) \]

Calculating \( 2^2 \):

\[ 2^2 = 4 \]

Now substituting this back into the equation:

\[ h(2) = 75 - 16 \times 4 \] \[ h(2) = 75 - 64 \] \[ h(2) = 11 \]

Therefore, the diver is 11 feet above the ocean after 2 seconds.