Write 0.4x +0.2y = 0.6 in slope-intercept form

3 answers

To convert the equation \(0.4x + 0.2y = 0.6\) into slope-intercept form, which is \(y = mx + b\) (where \(m\) is the slope and \(b\) is the y-intercept), follow these steps:

  1. Isolate \(y\) on one side of the equation. Start by moving \(0.4x\) to the other side:

    \[ 0.2y = -0.4x + 0.6 \]

  2. Divide every term by \(0.2\) to solve for \(y\):

    \[ y = -2x + 3 \]

Now, the equation \(y = -2x + 3\) is in slope-intercept form, where the slope \(m = -2\) and the y-intercept \(b = 3\).

y = __

The equation in slope-intercept form is:

\[ y = -2x + 3 \]

So, you can fill in the blank as:

\( y = -2x + 3 \)

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