Question
6CO2 + 6H2O to C6H12O6 + 4O2
How many molecules of carbon dioxide are involved in this reaction?
How many molecules of sugar are produced in this reaction?
How many atoms of carbon are on the left of the equation? How many on the right?
How many molecules of carbon dioxide are involved in this reaction?
How many molecules of sugar are produced in this reaction?
How many atoms of carbon are on the left of the equation? How many on the right?
Answers
GPT-4o mini
Let's analyze the reaction you've provided:
\[ 6 \text{CO}_2 + 6 \text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + 6 \text{O}_2 \]
1. **How many molecules of carbon dioxide are involved in this reaction?**
- There are **6 molecules** of carbon dioxide (CO₂) involved in this reaction.
2. **How many molecules of sugar are produced in this reaction?**
- The reaction produces **1 molecule** of glucose (C₆H₁₂O₆).
3. **How many atoms of carbon are on the left of the equation? How many on the right?**
- On the left side (reactants), each molecule of CO₂ has 1 carbon atom. Since there are 6 molecules of CO₂, there are \(6 \times 1 = 6\) carbon atoms.
- On the right side (products), each molecule of glucose (C₆H₁₂O₆) has 6 carbon atoms. Therefore, there are **6 carbon atoms on the right side**.
In summary:
- **6 molecules of CO₂** are involved.
- **1 molecule of sugar (C₆H₁₂O₆)** is produced.
- **6 carbon atoms** are present on both sides of the equation.
\[ 6 \text{CO}_2 + 6 \text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + 6 \text{O}_2 \]
1. **How many molecules of carbon dioxide are involved in this reaction?**
- There are **6 molecules** of carbon dioxide (CO₂) involved in this reaction.
2. **How many molecules of sugar are produced in this reaction?**
- The reaction produces **1 molecule** of glucose (C₆H₁₂O₆).
3. **How many atoms of carbon are on the left of the equation? How many on the right?**
- On the left side (reactants), each molecule of CO₂ has 1 carbon atom. Since there are 6 molecules of CO₂, there are \(6 \times 1 = 6\) carbon atoms.
- On the right side (products), each molecule of glucose (C₆H₁₂O₆) has 6 carbon atoms. Therefore, there are **6 carbon atoms on the right side**.
In summary:
- **6 molecules of CO₂** are involved.
- **1 molecule of sugar (C₆H₁₂O₆)** is produced.
- **6 carbon atoms** are present on both sides of the equation.