Asked by Anonymous
Evaluate
lim as x-> 0
square root (x+1) - square root (2x+1)
/ square root (3x+4) - square root (2x+4)
lim as x-> 0
square root (x+1) - square root (2x+1)
/ square root (3x+4) - square root (2x+4)
Answers
Answered by
Reiny
multiply by [√(3x+4) + √(2x+4)]/[√(3x+4) + √(2x+4)][(√x+1) + √(2x+1)]/[(√x+1) + √(2x+1)]
Expand only the factors which are the difference of squares pattern, leaving the other one alone.
Your limit should reduce to
-1([√(3x+4) + √(2x+4)]/[(√x+1) + √(2x+1)]
which as x --->
= -1(√4+√4)/(√1+√1)
= -2
Expand only the factors which are the difference of squares pattern, leaving the other one alone.
Your limit should reduce to
-1([√(3x+4) + √(2x+4)]/[(√x+1) + √(2x+1)]
which as x --->
= -1(√4+√4)/(√1+√1)
= -2
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