Tabitha works at a rate of 1 unit every 10 hours. Working together with a coworker, it only takes 5.24 hours to make 1 unit. Which of the following models is a rational equation that could determine the rate at which the coworker produces units?(1 point)Responsesx10=15.24Start Fraction x over 10 End Fraction equals Start Fraction 1 over 5.24 End Fraction15.24+1x=110Start Fraction 1 over 5.24 End Fraction plus Start Fraction 1 over x End Fraction equals Start Fraction 1 over 10 End Fraction110+1x=15.24Start Fraction 1 over 10 End Fraction plus Start Fraction 1 over x End Fraction equals Start Fraction 1 over 5.24 End Fraction15.24+110=1xStart Fraction 1 over 5.24 End Fraction plus Start Fraction 1 over 10 End Fraction equals Start Fraction 1 over x End Fraction

1 answer

To find a rational equation that determines the rate at which the coworker produces units, we start by identifying Tabitha's rate and the rate of her coworker.

Tabitha works at a rate of 1 unit every 10 hours, which gives her a rate of:

\[ R_T = \frac{1}{10} \text{ units per hour} \]

Let \( R_C \) be the rate (in units per hour) at which the coworker works. When they work together, they produce 1 unit in 5.24 hours, giving a combined rate of:

\[ R_{T+C} = \frac{1}{5.24} \text{ units per hour} \]

The relationship between their rates can be expressed as:

\[ R_T + R_C = R_{T+C} \]

Substituting the rates we know:

\[ \frac{1}{10} + R_C = \frac{1}{5.24} \]

To isolate \( R_C \), we can rewrite the equation:

\[ R_C = \frac{1}{5.24} - \frac{1}{10} \]

This rearrangement creates an equation that could be represented as a rational equation.

Among the options presented, the following equation aligns with this relationship:

\[ \frac{1}{10} + \frac{1}{x} = \frac{1}{5.24} \]

Where \( x \) represents the time in hours the coworker takes to produce 1 unit. Therefore, the correct model would be:

\[ \frac{1}{10} + \frac{1}{x} = \frac{1}{5.24} \]

So the correct response is:

Start Fraction 1 over 5.24 End Fraction plus Start Fraction 1 over x End Fraction equals Start Fraction 1 over 10 End Fraction