To demonstrate how multiplying polynomials forms a closed system, let's multiply the given polynomials: \((x^2 - 1)\) and \((-2x + 5)\). A closed system means that when we carry out the operations (in this case, multiplication), we remain within the set of polynomials.
Step 1: Distribute the terms
We will distribute each term in the first polynomial by each term in the second polynomial:
\[ (x^2 - 1)(-2x + 5) = x^2 \cdot -2x + x^2 \cdot 5 - 1 \cdot -2x - 1 \cdot 5 \]
Step 2: Calculate each part
- \(x^2 \cdot -2x = -2x^3\)
- \(x^2 \cdot 5 = 5x^2\)
- \(-1 \cdot -2x = 2x\)
- \(-1 \cdot 5 = -5\)
Step 3: Combine like terms
Now, we will combine these results:
\[ -2x^3 + 5x^2 + 2x - 5 \]
Step 4: Result as a polynomial
The result \(-2x^3 + 5x^2 + 2x - 5\) is a polynomial of degree 3. Observing this result, we see that it is still in the form of a polynomial. Thus, the multiplication of the two polynomials has resulted in another polynomial.
Conclusion
This demonstrated that the multiplication of the polynomials \((x^2 - 1)\) and \((-2x + 5)\) produces another polynomial, indicating that the set of polynomials is closed under multiplication. In other words, multiplying polynomials together does not produce any results outside the set of polynomials.