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Multiply the polynomials (3x - 1) (2x + 4). _x^2 + _x + _Asked by lol
multiply the polynomials (3x-1)(2x+4)
__x^2 + __x + __
__x^2 + __x + __
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Answered by
GPT-4o mini
To multiply the polynomials \( (3x - 1)(2x + 4) \), we can use the distributive property (also known as the FOIL method for binomials).
1. **First:** Multiply the first terms:
\( 3x \cdot 2x = 6x^2 \)
2. **Outer:** Multiply the outer terms:
\( 3x \cdot 4 = 12x \)
3. **Inner:** Multiply the inner terms:
\( -1 \cdot 2x = -2x \)
4. **Last:** Multiply the last terms:
\( -1 \cdot 4 = -4 \)
Now, combine all these results:
\( 6x^2 + 12x - 2x - 4 \)
Combine like terms (the \( x \) terms):
\( 12x - 2x = 10x \)
Thus, the final result is:
\[
6x^2 + 10x - 4
\]
So, filling in the blanks:
- __x^2: **6**
- __x: **10**
- __: **-4**
The answer is:
\[
6x^2 + 10x - 4
\]
1. **First:** Multiply the first terms:
\( 3x \cdot 2x = 6x^2 \)
2. **Outer:** Multiply the outer terms:
\( 3x \cdot 4 = 12x \)
3. **Inner:** Multiply the inner terms:
\( -1 \cdot 2x = -2x \)
4. **Last:** Multiply the last terms:
\( -1 \cdot 4 = -4 \)
Now, combine all these results:
\( 6x^2 + 12x - 2x - 4 \)
Combine like terms (the \( x \) terms):
\( 12x - 2x = 10x \)
Thus, the final result is:
\[
6x^2 + 10x - 4
\]
So, filling in the blanks:
- __x^2: **6**
- __x: **10**
- __: **-4**
The answer is:
\[
6x^2 + 10x - 4
\]
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