Question

A water tank decreases by 10 gallons every 3 hours each day. What is the total change in the amount of water in the tank after 6 days? (1 point)
Responses

-80 gallons
-80 gallons

-480 gallons
-480 gallons

80 gallons
80 gallons

480 gallons

Answer 1

To find the total change in the amount of water in the tank after 6 days, we start with the rate of decrease of water in the tank.

The water tank decreases by 10 gallons every 3 hours. First, we need to determine how many 3-hour periods are there in 6 days:

1. Calculate the total number of hours in 6 days:
\[
6 \text{ days} \times 24 \text{ hours/day} = 144 \text{ hours}
\]

2. Next, calculate how many 3-hour periods are in 144 hours:
\[
\frac{144 \text{ hours}}{3 \text{ hours/period}} = 48 \text{ periods}
\]

3. Now, calculate the total decrease in gallons over 48 periods, given that the tank decreases by 10 gallons in each period:
\[
48 \text{ periods} \times 10 \text{ gallons/period} = 480 \text{ gallons}
\]

Since the amount of water is decreasing, we denote the change as negative:
\[
\text{Total change} = -480 \text{ gallons}
\]

Thus, the total change in the amount of water in the tank after 6 days is **-480 gallons**.

The correct response is:
-480 gallons