Question
If a ball is thrown upward at 19.6 meters per second from the top of a building that is 25 meters high, the height of the ball can be modeled by Upper S equals 25 plus 19.6 t minus 4.9 t squared, where t is the number of seconds after the ball is thrown.
Answer parts a through c.
Question content area bottom
Part 1
a. Find the t-coordinate and S-coordinate of the vertex of the graph of this quadratic function.
The t-coordinate of the vertex of the graph of this quadratic function is tequals
enter your response here.
Answer parts a through c.
Question content area bottom
Part 1
a. Find the t-coordinate and S-coordinate of the vertex of the graph of this quadratic function.
The t-coordinate of the vertex of the graph of this quadratic function is tequals
enter your response here.
Answers
GPT-4o mini
To find the vertex of the quadratic function \( S(t) = 25 + 19.6t - 4.9t^2 \), we can use the formula for the \( t \)-coordinate of the vertex of a parabola given by the equation \( ax^2 + bx + c \), which is
\[
t = -\frac{b}{2a}
\]
Here, \( a = -4.9 \) and \( b = 19.6 \).
Now, substituting the values into the formula:
\[
t = -\frac{19.6}{2 \cdot -4.9}
\]
Calculating the denominator first:
\[
2 \cdot -4.9 = -9.8
\]
Now substituting this value back into the equation for \( t \):
\[
t = -\frac{19.6}{-9.8} = \frac{19.6}{9.8} = 2
\]
So, the \( t \)-coordinate of the vertex is \( t = 2 \) seconds.
Next, we need to find the \( S \)-coordinate of the vertex by substituting \( t = 2 \) back into the original function \( S(t) \):
\[
S(2) = 25 + 19.6(2) - 4.9(2^2)
\]
Calculating each term:
1. \( 19.6 \times 2 = 39.2 \)
2. \( 2^2 = 4 \)
3. \( 4.9 \times 4 = 19.6 \)
Putting it all together:
\[
S(2) = 25 + 39.2 - 19.6
\]
Performing the addition and subtraction:
1. \( 25 + 39.2 = 64.2 \)
2. \( 64.2 - 19.6 = 44.6 \)
Thus, the \( S \)-coordinate of the vertex is \( S = 44.6 \).
So, the final answers are:
- The \( t \)-coordinate of the vertex is \( t = 2 \).
- The \( S \)-coordinate of the vertex is \( S = 44.6 \).
\[
t = -\frac{b}{2a}
\]
Here, \( a = -4.9 \) and \( b = 19.6 \).
Now, substituting the values into the formula:
\[
t = -\frac{19.6}{2 \cdot -4.9}
\]
Calculating the denominator first:
\[
2 \cdot -4.9 = -9.8
\]
Now substituting this value back into the equation for \( t \):
\[
t = -\frac{19.6}{-9.8} = \frac{19.6}{9.8} = 2
\]
So, the \( t \)-coordinate of the vertex is \( t = 2 \) seconds.
Next, we need to find the \( S \)-coordinate of the vertex by substituting \( t = 2 \) back into the original function \( S(t) \):
\[
S(2) = 25 + 19.6(2) - 4.9(2^2)
\]
Calculating each term:
1. \( 19.6 \times 2 = 39.2 \)
2. \( 2^2 = 4 \)
3. \( 4.9 \times 4 = 19.6 \)
Putting it all together:
\[
S(2) = 25 + 39.2 - 19.6
\]
Performing the addition and subtraction:
1. \( 25 + 39.2 = 64.2 \)
2. \( 64.2 - 19.6 = 44.6 \)
Thus, the \( S \)-coordinate of the vertex is \( S = 44.6 \).
So, the final answers are:
- The \( t \)-coordinate of the vertex is \( t = 2 \).
- The \( S \)-coordinate of the vertex is \( S = 44.6 \).