It takes 1 molecule of nitrogen and 3

Question

molecules of hydrogen to produce 2
molecules of ammonia using the following formula:

1N2+ 3H2 → 2NH3

Identify which combination of molecules will produce ammonia with no leftovers?

(1 point)
Responses

5N2 and 6H2
5 n sub 2 and 6 h sub 2

8N2 and 4H2
8 n sub 2 and 4 h sub 2

4N2 and 4H2
4 n sub 2 and 4 h sub 2

2N2 and 6H2

Answer 1

To determine which combination of molecules will produce ammonia (NH3) with no leftovers, we can use the balanced equation:

\[ 1 \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3 \]

This means that for every 1 molecule of nitrogen (N2), we need 3 molecules of hydrogen (H2) to produce 2 molecules of ammonia (NH3).

Now, let's analyze each combination provided to see if they fit this stoichiometry with no leftovers:

1. 5 N2 and 6 H2

   • N2: \( 5 \) (produces \( 5 \times 2 = 10 \) NH3)
   • H2: \( 6/3 = 2 \) (can only produce \( 2 \times 2 = 4 \) NH3)
   • Leftovers: Yes (N2 can produce more NH3 than H2 can supply)

2. 8 N2 and 4 H2

   • N2: \( 8 \) (produces \( 8 \times 2 = 16 \) NH3)
   • H2: \( 4/3 \approx 1.33 \) (same as \( 1 \) N2 can produce \( 1 \times 2 = 2 \) NH3)
   • Leftovers: Yes (N2 can produce more NH3 than H2 can supply)

3. 4 N2 and 4 H2

   • N2: \( 4 \) (produces \( 4 \times 2 = 8 \) NH3)
   • H2: \( 4/3 \approx 1.33 \) (same as \( 1 \) N2 can produce \( 1 \times 2 = 2 \) NH3)
   • Leftovers: Yes (H2 is limited to produce only 2 NH3)

4. 2 N2 and 6 H2

   • N2: \( 2 \) (produces \( 2 \times 2 = 4 \) NH3)
   • H2: \( 6/3 = 2 \) (produces \( 2 \times 2 = 4 \) NH3)
   • Leftovers: No (both N2 and H2 produce 4 NH3 with no leftovers)

Thus, the correct combination that produces ammonia with no leftovers is:

2 N2 and 6 H2.