To simplify the expression \((4x^{-4}y^{0})^{-2}\), we can follow the rules of exponents step by step.
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Recall that \(y^{0} = 1\): \[ 4x^{-4}y^{0} = 4x^{-4} \cdot 1 = 4x^{-4} \]
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Apply the negative exponent rule: The rule states that \((a^m)^{-n} = a^{-mn} = \frac{1}{a^{mn}}\).
Thus, we have: \[ (4x^{-4})^{-2} = 4^{-2}(x^{-4})^{-2} \]
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Simplify each component:
- For \(4^{-2}\): \[ 4^{-2} = \frac{1}{4^2} = \frac{1}{16} \]
- For \((x^{-4})^{-2}\): \[ (x^{-4})^{-2} = x^{8} \text{ (since } -4 \cdot -2 = 8\text{)} \]
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Combine the results: \[ (4x^{-4})^{-2} = \frac{1}{16} \cdot x^{8} = \frac{x^8}{16} \]
Therefore, the simplified expression is: \[ \frac{x^8}{16} \]